tập hợp các giá trị nguyên thỏa mãn/x+2015/+2016=2017
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/x+2014/+2015=2016
=>/x+2014/=2016-2015
=>/x+2014/=1
=>x+2014=1 hoặc x+2014=-1
*nếu x+2014=1
=> x=1-2014
=> x=-2013
*nếu x+2014=-1
=> x=-1-2014
=> x=-2015
vậy x thuộc {-2015;-2013}
mk thi rùi đúng 100%
\(\frac{x}{2015}+\frac{x}{2016}=\frac{x}{2016}+\frac{x}{2017}\)
\(\Rightarrow\frac{x}{2015}+\frac{x}{2016}-\frac{x}{2016}-\frac{x}{2017}=0\)
\(\Rightarrow\frac{x}{2015}-\frac{x}{2017}=0\)
\(\Rightarrow x.\left(\frac{1}{2015}-\frac{1}{2017}\right)=0\)
Mà ta thấy \(\frac{1}{2015}-\frac{1}{2017}\ne0\Rightarrow x=0\)
Vậy \(x=0\)
\(\frac{x}{2015}+\frac{x}{2016}=\frac{x}{2016}+\frac{x}{2017}\)
\(\Leftrightarrow\frac{x}{2015}+\frac{x}{2016}-\frac{x}{2016}-\frac{x}{2017}=0\)
\(\Leftrightarrow x\left(\frac{1}{2015}+\frac{1}{2016}-\frac{1}{2016}-\frac{1}{2017}\right)=0\)
\(\Leftrightarrow x=0\).Do \(\frac{1}{2015}+\frac{1}{2016}-\frac{1}{2016}-\frac{1}{2017}\ne0\)
Vậy giá trị của x là x=0
\(\left|\frac{x}{2015}+\frac{x}{2016}\right|=\left|\frac{x}{2016}+\frac{x}{2017}\right|\)
<=>\(\left|x\right|.\left|\frac{1}{2015}+\frac{1}{2016}\right|=\left|x\right|.\left|\frac{1}{2016}+\frac{1}{2017}\right|\)
<=>\(\left|x\right|.\left(\frac{1}{2015}+\frac{1}{2016}\right)=\left|x\right|.\left(\frac{1}{2016}+\frac{1}{2017}\right)\)
<=>\(\left|x\right|.\left(\frac{1}{2015}+\frac{1}{2016}\right)-\left|x\right|.\left(\frac{1}{2016}+\frac{1}{2017}\right)=0\)
<=>\(\left|x\right|.\left(\frac{1}{2015}+\frac{1}{2016}-\frac{1}{2016}-\frac{1}{2017}\right)=0\)
<=>\(\left|x\right|.\left(\frac{1}{2015}-\frac{1}{2017}\right)=0\)
Vì \(\frac{1}{2015}-\frac{1}{2017}\ne0\Rightarrow\left|x\right|=0\Rightarrow x=0\)
Vậy x=0
\(\left|\frac{x}{2015}+\frac{x}{2016}\right|=\left|\frac{x}{2016}+\frac{x}{2017}\right|\)
\(\Rightarrow\left|x.\left(\frac{1}{2015}+\frac{1}{2016}\right)\right|=\left|x.\left(\frac{1}{2016}+\frac{1}{2017}\right)\right|\)
\(\Rightarrow\left|x\right|.\left|\frac{1}{2015}+\frac{1}{2016}\right|=\left|x\right|.\left|\frac{1}{2016}+\frac{1}{2017}\right|\)
\(\Rightarrow\left|x\right|.\left(\frac{1}{2015}+\frac{1}{2016}\right)=\left|x\right|.\left(\frac{1}{2016}+\frac{1}{2017}\right)\)
Mà \(\frac{1}{2015}+\frac{1}{2016}>\frac{1}{2016}+\frac{1}{2017}\)
=> |x| = 0
=> x = 0
Vậy x = 0
| x + 2014 | + 2015 = 2016
=> | x + 2014 | = 2016 - 2015
=> | x + 2014 | = 1
=> x + 2014 = 1 hoặc - 1
TH1 : x + 2014 = 1 => x = 1 - 2014 => x = - 2013
TH2 : x + 2014 = - 1 => x = - 1 - 2014 => x = - 2015
Vậy x = -2013 hoặc x = - 2015
\(\frac{x}{2015}+\frac{x}{2016}=\frac{x}{2016}+\frac{x}{2017}\)
=>\(\frac{x}{2015}=\frac{x}{2017}\)
Vì 2015 khác 2017. Nên x=0
|x+2015|+2016=2017
|x+2015|=2017-2016
|x+2015|=1
|x+2015|=+1
=>x+2015=1=>x=-2014
=>x+2015=-1=>x=-2016
Vay .....................
k mik nha ban
ta co:/x+2015/=2017-2016=1
{x+2015=1;x=-2014
x+2015=-1;x=-2016