7x.(2+x)-7x.(x+3)=14
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7x.(2+x)-7x.(x+3)=14
7x.[(2+x)-(x+3)]=14
7x.[x+2-x-3]=14
7x.(-1) =14
7x =14:(-1)
7x =-14
x =-14:7
x =-2
Chúc bn học tốt
\(7x\cdot\left(2+x\right)-7x\cdot\left(x+3\right)=14\)
\(7x\cdot\left(2+x-x-3\right)=14\)
\(7x\cdot\left(-1\right)=14\)
\(7x=-14\)
\(x=-2\)
7x(2+x )- 7x (x+3) = 14
<=> 14x + 7x2 - 7x2 - 21x = 14
<=> -7x = 14
<=> x = -2
7x.(2+x)-7x.(x+3)=14
7x.[(2+x)-(3+x)]=14
7x.[2+x-3-x]=14
7x.(-1) =14
7x =14:(-1)
7x =-14
x =-14:7
x =-2
Chúc bn học tốt
\(7x\left(2+x\right)-7x\left(x+3\right)=14\)
\(\Leftrightarrow14x+7x^2-7x^2-21x=14\)
\(\Leftrightarrow-7x=14\)\(\Leftrightarrow x=-2\)
Vậy \(x=-2\)
7x.(2+x)-7x.(x+3)=14
7x.(2+x-x-3)=14
7x.(-1)=14
7x=14:(-1)
7x=-14
x=-14:7
x=2
Vậy x=2
tk nha!
\(7x\left(2+x\right)-7x\left(x+3\right)=14\)
\(\Rightarrow7x\left[\left(2+x\right)-\left(x+3\right)\right]=14\)
\(\Rightarrow7x\left[2+x-x-3\right]=14\)
\(\Rightarrow7x.\left(-1\right)=14\)
\(\Rightarrow-7x=14\)
\(\Rightarrow x=14:-7\)
\(\Rightarrow x=-2\)
Vậy x = -2
_Chúc bạn học tốt_
+ -2X-12+6X-60=8
<=>4X=80]
<=> X = 20
V.....
+ -8X-36 +8X -3 - X - 13 =0
<=> -X = 52
<=> X = -52
V.....
+ 14X +7\(X^2\)-7\(X^2\)-21X=14
<=> -7X =14
<=> X= -2
V .......
a: \(x^2\left(x-3\right)-4x+12\)
\(=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)
b: \(2a\left(x+y\right)+x+y=\left(x+y\right)\left(2a+1\right)\)
c: \(6x^2-12x-7x+14\)
\(=6x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(6x-7\right)\)
a.
-2 (x+6)+6 (x-10)=8
-2x -12 +6x -60 =8
4x -72 =8
4x = -64
x= -16
b.
7x (2+x) -7x (x+3) =14
7x [ (2+x)-(x+3) ] =14
7x (2+x-x-3) =14
-7x =14
x= -2
a: \(\dfrac{x^2-5x+6}{x^2+7x+12}:\dfrac{x^2-4x+4}{x^2+3x}\)
\(=\dfrac{\left(x-2\right)\left(x-3\right)}{\left(x+3\right)\left(x+4\right)}\cdot\dfrac{x\left(x+3\right)}{\left(x-2\right)^2}\)
\(=\dfrac{x\left(x-3\right)}{\left(x-2\right)\left(x+4\right)}\)
b: \(\dfrac{x^2+2x-3}{x^2+3x-10}:\dfrac{x^2+7x+12}{x^2-9x+14}\)
\(=\dfrac{\left(x+3\right)\left(x-1\right)}{\left(x+5\right)\left(x-2\right)}\cdot\dfrac{\left(x-2\right)\left(x-7\right)}{\left(x+3\right)\left(x+4\right)}\)
\(=\dfrac{\left(x-1\right)\left(x-7\right)}{\left(x+5\right)\left(x+4\right)}\)
\(7x.\left(2+x\right)-7x.\left(x+3\right)=14\)
\(7x.\left(2+x-x-3\right)=14\)
\(7x.\left(-1\right)=14\)
\(7x=14:\left(-1\right)\)
\(7x=-14\)
\(x=\left(-14\right):7\)
\(x=-2\)
7x.( 2 + x ) - 7x( x + 3 ) = 14
<=> 7x( 2 + x - x - 3 ) = 14
<=> 7x.(-1) = 14
<=> -7x = 14
<=> x = -2