200:{80-[26+(5-3)²]}
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253 = 200 + 50 + 3
675 = 600 + 70 + 5
810 = 800 + 10
508 = 500 + 8
300 + 20 + 7 = 327
400 + 80 + 2 = 482
300 + 5 = 305
700 + 80 = 780
a) x = 2.
b) x = 7.
c) x= 12.
d) x= 45.
e) x = 18.
f) x = 10.
a) 156 - 2 . x = 80
2 . x = 156 - 80
2 . x = 76
x= 76 : 2
x = 38
b) 315 + 5 . x = 200
5 . x = 200 - 315
5 . x = -115
x= -115 : 5
x = -23
c) 5 . ( x + 3 ) - 20 = 40
5 . ( x +3) = 40+20
5. ( x + 3) =60
x +3 =60:5
x + 3= 12
x = 12 - 3
x =9
\(a,210-5\left(x-11\right)=200\\ \Rightarrow5\left(x-11\right)=10\\ \Rightarrow x-11=2\\ \Rightarrow x=13.\\ b,\left(2x+1\right):7=2^2+3^2\\ \Rightarrow\left(2x+1\right):7=4+9\\ \Rightarrow\left(2x+1\right):7=13\\ \Rightarrow2x+1=91\\ \Rightarrow2x=90\\ \Rightarrow x=45.\\ c,450:\left[41-\left(2x-5\right)\right]=3^2.5\\ \Rightarrow450:\left[41-\left(2x-5\right)\right]=45\\ \Rightarrow41-\left(2x-5\right)=10\\ \Rightarrow2x-5=31\\ \Rightarrow2x=36\\ \Rightarrow x=18.\\ d,\left(5x-9\right).7+3=80\\ \Rightarrow\left(5x-9\right).7=77\\ \Rightarrow5x-9=11\\ \Rightarrow5x=20\\ \Rightarrow x=4.\)
a) \(210-5\left(x-11\right)=200\)
\(5.\left(x-11\right)=210-200\)
\(5.\left(x-11\right)=10\)
\(x-11=10:5\)
\(x-11=2\)
\(x=2+11\)
\(x=13\)
b) \(\left(2x+1\right):7=2^2+3^2\)
\(\left(2x+1\right):7=13\)
\(2x+1=13.7\)
\(2x=91-1\)
\(2x=90\)
\(x=90:2\)
\(x=45\)
c) \(450:\left[41-\left(2x-5\right)\right]=3^2.5\)
\(450:\left[41-\left(2x-5\right)\right]=45\)
\(\left[41-\left(2x-5\right)\right]=450:45\)
\(\left[41-\left(2x-5\right)\right]=10\)
\(2x-5=41-10\)
\(2x-5=31\)
\(2x=31+5\)
\(2x=36\)
\(x=36:2\)
\(x=18\)
d) \(\left(5x-9\right).7+3=80\)
\(\left(5x-9\right).7=80-3\)
\(5x-9=77:7\)
\(5x-9=11\)
\(5x=11+9\)
\(5x=20\)
\(x=20:5\)
\(x=4\)
a) 125 x 45 + 45 x 25 + 90 x 25
=125 x 45 + 45 x 25 + 2 x 45 x 25
=45 x [125 + 25 + ( 2 x 25 )]
=45 x [125 + 25 + 50]
=45 x 200
= 9000
c) 25 x 20 x 4 - 200 x 40
=25 x 2 x 10 x 4 - 200 x 40
=(25 x 2 x 4) x 10 - 200 x 40
=200 x 10 - 200 x 40
=200 x (10 - 40)
=200 x (-30)
= -6000
A = 1+2+3+...+200
A = \(\frac{200.201}{2}\)
A = 20100 (cái này là quy tắc nha)
B = 2+4+6+...+80
B có : (80 - 2) : 2 + 1 = 40 ( số hạng )
B = [(80 + 2) . 40] : 2 =1640.
C = 1+3+5+...+81
C có : ( 81 - 1 ) : 2 + 1 = 41 ( số hạng )
C = ( 81 + 1 ) . 41 : 2 = 1681
(\(\dfrac{2}{3}\) + \(\dfrac{8}{9}\) + \(\dfrac{26}{27}\) + \(\dfrac{80}{81}\) + \(\dfrac{242}{243}\)) : y = 5
Đăt A = \(\dfrac{2}{3}\) + \(\dfrac{8}{9}\) + \(\dfrac{26}{27}\) + \(\dfrac{80}{81}\) + \(\dfrac{242}{243}\)
3A = 2 + \(\dfrac{8}{3}\) + \(\dfrac{26}{9}\) + \(\dfrac{80}{27}\) + \(\dfrac{242}{81}\)
3A - A = 2 + \(\dfrac{8}{3}\) + \(\dfrac{26}{9}\) + \(\dfrac{80}{27}\) + \(\dfrac{242}{81}\) - \(\dfrac{2}{3}\)-\(\dfrac{8}{9}\)-\(\dfrac{26}{27}\)-\(\dfrac{80}{81}\)-\(\dfrac{242}{243}\)
A x (3 - 1) = 2 - \(\dfrac{242}{243}\)+ (\(\dfrac{8}{3}\) - \(\dfrac{2}{3}\))+(\(\dfrac{26}{9}\) - \(\dfrac{8}{9}\))+(\(\dfrac{80}{27}\)-\(\dfrac{26}{27}\))+(\(\dfrac{242}{81}\)-\(\dfrac{80}{81}\))-\(\dfrac{242}{243}\)
A x 2 = 2 - \(\dfrac{242}{243}\) + 2 + 2 + 2 + 2
A x 2 = (2 + 2 + 2 +2 + 2) - \(\dfrac{242}{243}\)
A x 2 = 2x5 - \(\dfrac{242}{243}\)
A x 2 = 10 - \(\dfrac{242}{243}\)
A x 2 = \(\dfrac{2188}{243}\)
A = \(\dfrac{2188}{243}\) : 2
A = \(\dfrac{1094}{243}\)
\(\dfrac{1094}{243}\) : y = 5
y = \(\dfrac{1094}{243}\) : 5
y = \(\dfrac{1094}{1215}\)
200 :{ 80 - [ 26 + ( 5-3)2]}
= 200 : { 80- [ 26 + 22]}
= 200 : { 80 - [ 26 + 4]}
= 200 : { 80 - 30}
= 200 : 50
= 4
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