1/Tính bằng cách thuận tiện nhất:
a) (98,7 + 123 ) + 1,3
b) 4*23*25
c) 1/15 + 1/14 + 14/15
d) 3*21 + 4*21 + 21*93
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a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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Bài 4:
a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)
b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)
Bài 4:
a: =11/21(7/4+5/4)=11/21x3=11/7
b: =6/13(23/14-9/14)=6/13
a, \(\frac{6}{7}.\frac{16}{15}.\frac{7}{6}.\frac{21}{32}=\frac{6}{7}.\frac{7}{6}.\frac{16}{15}.\frac{21}{32}\)=\(1.\frac{16}{15}.\frac{21}{32}=\frac{7}{5.2}=\frac{7}{10}\)
Phần b T2
c,\(\frac{7}{4}.\frac{11}{21}+\frac{11}{21}.\frac{5}{4}=\frac{11}{21}.\left(\frac{7}{4}+\frac{5}{4}\right)\)=\(\frac{11}{21}.3=\frac{11}{7}\)
A. = 14/15 * 15/23 * 23/21
= 14/23 * 23/21
= 14/21
B. = 1/2 * (9/10 + 8/10 - 7/10)
= 1/2 * 10/10
= 1/2 * 1
= 1/2
a) \(\frac{14}{15}\cdot\frac{23}{21}\cdot\frac{15}{23}=\frac{14}{21}=\frac{2}{3}\)
b)\(\frac{1}{2}\cdot\frac{9}{10}+\frac{1}{2}\cdot\frac{8}{10}-\frac{1}{2}\cdot\frac{7}{10}=\frac{1}{2}\cdot\left(\frac{9}{10}+\frac{8}{10}-\frac{7}{10}\right)=\frac{1}{2}\cdot1=\frac{1}{2}\)
a. 19 + 18 + 17 + 16 + 14 + 21 + 22 + 23 + 24 + 26
= (19 + 21) + (18 + 22) + (17 + 23) + (16 + 24) + (14 + 26)
= 40 + 40 + 40 + 40 + 40
= 40 x 5
= 200
a) ( 98,7 + 123 ) + 1,3
= ( 98,7 + 1,3 ) + 123
= 100 + 123
= 223
b) 4 x 23 x 25
= 4 x 25 x 23
= 100 x 23
= 2300
c) \(\frac{1}{15}+\frac{1}{14}+\frac{14}{15}\)
\(=\left(\frac{1}{15}+\frac{14}{15}\right)+\frac{1}{14}\)
\(=1+\frac{1}{14}\)
\(=\frac{15}{14}\)
d) 3 x 21 + 4 x 21 + 21 x 93
= ( 3 + 4 + 93 ) x 21
= 100 x 21
= 2100
a) (98,7 + 123 ) + 1,3 =(98,7 + 1,3 ) + 123 =100+123=223. b)4*23*25 =25*4*23=100*23=2300. c)1/15 + 1/14 +14/15 =(1/15+14/15) + 1/14 =1+1/14=15/14 d)3*21+4*21+21*93 =21*(3+4+93)=21*1100=2100.