4/3x7 + 5/7x12 + 1/12x13 + 7/13x20 + 3/20x23
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4/3x7 + 5/7x12 + 1/12x13 + 7/13x20 + 3/20x23
=1/3-1/7+1/7-1/12+1/12-1/13+1/13-1/20+1/20-1/23
=1/3-1/23
=20/69
Kanzaki Mizuki
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+\frac{1}{13}-\frac{1}{20}+\frac{1}{20}-\frac{1}{23}\)
\(=\frac{1}{3}-\frac{1}{23}\)
\(=\frac{20}{69}\)
a = 1/5-1/8 +1/8-1/11+....+1/602-1/605 = 1/5-(1/8-1/8) -(1/11-1/11)-......-(1/602-1/602)-1/605
1/5-1/605=120/605=24/121
câu b bạn làm tương tự nhé
nhanh giúp mình đi các bạn,nếu giúp mình mà đúng thì mình tk cho
Tính thuận giúp 4/3x7 + 5/7x12 + 1/12x13 + 7/13x20 + 3/20x 23
chú ý : x là chữ x không phải dấu nhân
\(\frac{16x17-5}{16x16+11}=\frac{16x16+16-5}{16x16+11}=1\)
\(\frac{4}{3x7}+\frac{5}{7x12}+\frac{1}{12x13}+....+\frac{3}{20x23}\)
=\(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{20}-\frac{1}{23}\)
=\(\frac{1}{3}-\frac{1}{23}=\frac{20}{69}\)
a) \(\frac{16\cdot17-5}{16\cdot16+11}\)
= \(\frac{16\cdot16+16-5}{16\cdot16+11}\)
= \(\frac{16\cdot16+11}{16\cdot16+11}=1\)
A = \(\dfrac{4}{3.7}\) + \(\dfrac{5}{7.12}\) + \(\dfrac{1}{12.13}\) + \(\dfrac{7}{13.20}\) + \(\dfrac{3}{20.23}\)
A = \(\dfrac{1}{3}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\) - \(\dfrac{1}{12}\) + \(\dfrac{1}{12}\) - \(\dfrac{1}{13}\) + \(\dfrac{1}{13}\) - \(\dfrac{1}{20}\) + \(\dfrac{1}{20}\)- \(\dfrac{1}{23}\)
A = \(\dfrac{1}{3}\) - \(\dfrac{1}{23}\)
A = 20/69
A = \dfrac{4}{3.7}3.74 + \dfrac{5}{7.12}7.125 + \dfrac{1}{12.13}12.131 + \dfrac{7}{13.20}13.207 + \dfrac{3}{20.23}20.233
A = \dfrac{1}{3}31 - \dfrac{1}{7}71 + \dfrac{1}{7}71 - \dfrac{1}{12}121 + \dfrac{1}{12}121 - \dfrac{1}{13}131 + \dfrac{1}{13}131 - \dfrac{1}{20}201 + \dfrac{1}{20}201- \dfrac{1}{23}231
A = \dfrac{1}{3}31 - \dfrac{1}{23}231