3+6+9+12+15+18+21+24+27=?
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Đặt
- 5,4:0,4 × 1420 + 4,5 × 780 × 3
= 13,5 × 1420 + 13,5 × 780
= 13,5 × 1420 + 780
= 13,5 × 2200
= 29700
- 3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27
= 3 + 27 + 6 + 24 + 9 + 21 + 12 + 18 + 15
= 30 + 30 + 30 + 30 + 15
= 30 × 4 + 15
= 120 + 15
= 135
\(\Rightarrow\)\(\frac{29700}{135}\)
\(\frac{\text{5,4:0,4x1420+4,5x780x3}}{3+6+9+12+15+18+21+24+27}\)=220
Phương pháp giải:
Nhẩm bảng chia 3 rồi điền kết quả vào chỗ trống.
Lời giải chi tiết:
3 : 3 = 1 12 : 3 = 4
6 : 3 = 2 15 : 3 = 5
9 : 3 = 3 27 : 3 = 9
18 : 3 = 6 21 : 3 = 7
24 : 3 = 8
Phương pháp giải:
Nhẩm bảng chia 3 rồi điền kết quả vào chỗ trống.
Lời giải chi tiết:
9 : 3 = 3 6 : 3 = 2
3 : 3 = 1 15 : 3 = 5
12 : 3 = 4 21 : 3 = 7
18 : 3 = 6 24 : 3 = 8
27 : 3 = 9 30 : 3 = 10
câu 1)
\(\dfrac{-12}{18}+\left(\dfrac{-21}{35}\right)=\dfrac{-19}{15}\)
câu 2)
\(-\dfrac{3}{21}+\dfrac{6}{42}=0\)
câu 3)
\(-\dfrac{18}{24}+\dfrac{15}{21}=-\dfrac{1}{28}\)
câu 4)
\(\dfrac{1}{6}+\dfrac{2}{5}=\dfrac{17}{30}\)
câu 5)
\(\dfrac{3}{5}+\left(-\dfrac{7}{4}\right)=-\dfrac{23}{20}\)
câu 6)
\(\left(-2\right)+\left(\dfrac{-5}{8}\right)=\dfrac{-21}{8}\)
câu 7)
\(\dfrac{1}{-8}+\left(-\dfrac{5}{9}\right)=-\dfrac{49}{72}\)
câu 8)
\(\dfrac{4}{13}+\dfrac{12}{39}=\dfrac{8}{13}\)
câu 9)
\(\dfrac{1}{21}+\dfrac{1}{28}=\dfrac{1}{12}\)
câu 10)
\(-\dfrac{3}{29}+\dfrac{16}{58}=\dfrac{5}{29}\)
câu 11)
\(\dfrac{8}{40}+\left(-\dfrac{36}{45}\right)=-\dfrac{3}{5}\)
câu 12)
\(-\dfrac{8}{18}+\left(-\dfrac{15}{27}\right)=-1\)
câu 13)
\(\dfrac{13}{30}+\left(-\dfrac{1}{5}\right)=\dfrac{7}{30}\)
câu 14)
\(\dfrac{2}{21}+\dfrac{1}{28}=\dfrac{11}{84}\)
câu 15)
\(5+\left(-\dfrac{3}{4}\right)=\dfrac{17}{4}\)
câu 16)
\(\dfrac{18}{24}+\dfrac{45}{-10}=-\dfrac{15}{4}\)
\(\frac{x^{24}+x^{18}+x^{12}+x^6+1}{x^{27}+x^{24}+x^{21}+x^{18}+x^{15}+x^{12}+x^9+x^6+x^3+1}=\frac{x^{24}+x^{18}+x^{12}+x^6+1}{x^{24}\left(x^3+1\right)+x^{18}\left(x^3+1\right)+x^{12}\left(x^3+1\right)+x^6\left(x^3+1\right)+\left(x^3+1\right)}\)
=\(\frac{x^{24}+x^{18}+x^{12}+x^6+1}{\left(x^3+1\right)\left(x^{24}+x^{18}+x^{12}+x^6+1\right)}=\frac{1}{x^3+1}\)
cau 1 sai de
cau 2 :
3+6+9+12+15+18+21+24+27= (3+27)+(6+34)+(9+21)+(12+18)+15= 30+30+30+30+15=135
\(5,4:0,4\times1420+4,5\times780\times3\)
\(=13,5\times1420+13,5\times780\)
\(=13,5\times\left(1420+780\right)\)
\(=13,5\times2200\)
\(=29700\)
\(3+6+9+12+15+18+21+24+27\)
\(=\left(3+27\right)+\left(6+24\right)+\left(9+21\right)+\left(12+18\right)+15\)
\(=30+30+30+30+15\)
\(=30\times4+15\)
\(=120+15\)
\(=135\)
Xét \(x^{27}+x^{24}+x^{21}+x^{18}+x^{15}+x^{12}+x^9+x^6+x^3+1\)
\(=\left(x^{27}+x^{21}+x^{15}+x^9+x^3\right)+\left(x^{24}+x^{18}+x^{12}+x^6+1\right)\)
\(=x^3\left(x^{24}+x^{18}+x^{12}+x^6+1\right)+\left(x^{24}+x^{18}+x^{12}+x^6+1\right)\)
\(=\left(x^3+1\right)\left(x^{24}+x^{18}+x^{12}+x^6+1\right)\)
Vậy ta có
\(VT=\dfrac{x^{24}+x^{18}+x^{12}+x^6+1}{\left(x^3+1\right)\left(x^{24}+x^{18}+x^{12}+x^6+1\right)}=\dfrac{1}{x^3+1}\) (đpcm)
3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27
= 135
3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27
= (3 + 27) + (6 + 24) + (9 + 21) + (12 + 18) + 15
= 30 + 30 + 30 + 30 + 15
= 30 x 4 + 15
= 120 + 15
= 135