71+x-(-24x)+(35-x)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) 35 x 2 x 9 x 5
= (35 x 9) x (2 x 5)
= (35 x 10 - 35) x 10
= (350 - 35) x 10
= 315 x 10 = 3150
b) 24 x 71 + 71 x 75 + 71
= 71 x (24+75+1)
=71 x 100
= 7100
(71+x)-(-24-x)= -(35-x)
71+x+24+x = -35+x
71+24+2x = -35+x
95+2x = -35+x
95+x = -35
x = -35-95
x = -130
a: \(\left(2x+1\right)\left(2x+3\right)\left(x+1\right)^2-18\)
\(=\left[\left(2x+2\right)^2-1\right]\left(x+1\right)^2-18\)
\(=4\left(x+1\right)^4-\left(x+1\right)^2-18\)
\(=4\left(x+1\right)^4-9\left(x+1\right)^2+8\left(x+1\right)^2-18\)
\(=\left(x+1\right)^2\left[4\left(x+1\right)^2-9\right]+2\left[4\left(x+1\right)^2-9\right]\)
\(=\left[\left(2x+2\right)^2-9\right]\left[\left(x+1\right)^2+2\right]\)
\(=\left(2x+5\right)\left(2x-1\right)\left(x^2+2x+3\right)\)
b: \(\left(x^2+4x+3\right)\left(x^2+12x+35\right)+15\)
\(=\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15\)
\(=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\)
\(=\left(x^2+8x\right)^2+22\left(x^2+8x\right)+105+15\)
\(=\left(x^2+8x\right)^2+22\left(x^2+8x\right)+120\)
\(=\left(x^2+8x+10\right)\left(x^2+8x+12\right)\)
\(=\left(x^2+8x+10\right)\left(x+2\right)\left(x+6\right)\)
c: \(\left(x-3\right)\left(x-5\right)\left(x-6\right)\left(x-10\right)-24x^2\)
\(=\left(x^2-13x+30\right)\left(x^2-11x+30\right)-24x^2\)
\(=\left(x^2+30\right)^2-24x\left(x^2+30\right)+143x^2-24x^2\)
\(=\left(x^2+30\right)^2-24x\left(x^2+30\right)+119x^2\)
\(=\left(x^2-17x+30\right)\left(x^2-7x+30\right)\)
\(=\left(x-2\right)\left(x-15\right)\left(x^2-7x+30\right)\)
M = (71+ x) - (-24 - x) + (-35 - x)
= 71 + x + 24 + x - 35 - x
= (x + x - x) + (71 + 24 - 35)
= x + 60
M = ( 71 + x ) - ( - 24 - x ) + ( - 35 - x )
= 71 + x + 24 + x - 35 - x
= ( x + x - x ) + ( 71 + 24 - 35 )
= x + 60
a) (71+x)-(-24-x)+(-35-x)=0 b)x-34-[(15+x)-(23-x)]=0
71+x+24+x+-35-x =0 x-34-15-x-23+x =0
(x+x-x)+(71+24-35) =0 (x-x+x)+(-34-15-23) =0
x+60 =0 x+-72 =0
x =0-60 x =0-(-72)
x = -60 x = 72
mk chỉ làm ý A thui nha
\(A=\left(71+x\right)-\left(-24-x\right)+\left(-35-x\right)\)
\(A=71+x+24+x+\left(-35\right)-x\)
\(A=\left[71+24+\left(-35\right)\right]+\left(x+x-x\right)\)
\(A=60+x\)
Vậy \(A=60+x\)
\(a,A=\left(71+x\right)-\left(-24-x\right)+\left(-35-x\right)\)
\(=71+x+24+x-35-x\)
\(=60+x\)
\(b,B=x-34-\left[\left(15+x\right)-\left(23-x\right)\right]\)
\(=x-34-\left(15+x-23+x\right)\)
\(=x-34-15-x+23-x\)
\(=-x-26\)
71+x-(-24x)+(35-x)
=71+x+24x-35+x
=(71+24-35)+(x+24x+x-35x)
= 60 + -9x
= 60+(-9x)
K cho mình nhé.
71 + x -(-24x) + (35 -x)
= 71 + x + 24 x + 35 - x
= 106 + 23x
thêm vế phải nữa để tìm ra x nhé