Tính nhanh
5\3+5/9+5/27+...+5/218
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\(\frac{5+\frac{5}{3}+\frac{5}{9}+\frac{5}{27}}{2+\frac{2}{3}+\frac{2}{9}+\frac{2}{27}}=\frac{5.\left(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\right)}{2.\left(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\right)}=\frac{5}{2}=2\frac{1}{2}\)
`a: =(7/3-4/3)+11/5=16/5`
`b: =(18/13-5/13)+55/46=1+55/46=101/46`
`c: =27/25-4/9-2/25+5/9=(27/25-2/25)+(5/9-4/9)=1+1/9=10/9`
2 x 5 + 5 x 7 + 9 x 3
= 5 x ( 2 + 7 ) + 9 x 3
= 5 x 9 + 9 x 3
= 9 x ( 5 + 3 )
= 9 x 8
= 72
2x5+5x9+9x3 15:5+27:5+8:5
=9x5+(2+3) =(15+8+27):5
=9x5+5 =50:5
=9x5+5x1 =10
=5x(9+1) 9+9x3+18:2x6
=5x10 =1x9+9x3+9x6
=50 =9x(1+6+3)
=9x10
=90
2/3 x 4/5 + 4/5 x 8/3 = 4/5 x (2/3 + 8/3) = 4/5 x 10/3 = 8/3
27/32 x 16/9 -27/32 x7/9 + 27/32
= 27/32 x (16/9 - 7/9 + 1 )
=27/32 x 2
=27/16
\(\frac{2}{3}\) x \(\frac{4}{5}\) + \(\frac{4}{5}\) x \(\frac{8}{3}\)
=\(\frac{4}{5}\) x ( \(\frac{2}{3}\) + \(\frac{8}{3}\) )
= \(\frac{4}{5}\) x \(\frac{10}{3}\)
= \(\frac{40}{15}\) = \(\frac{8}{5}\)
5 + 5/3 + 5/9 + 5/27 + 5/81
= 5/1 + 5/3 + 5/9 + 5/27 + 5/81
= 405/81 + 135/81 + 15/81 + 5/81
= 605/81
\(\frac{\frac{1}{3}+\frac{1}{9}-\frac{1}{27}}{\frac{5}{3}+\frac{5}{9}-\frac{5}{27}}=\frac{\frac{9}{27}+\frac{3}{27}-\frac{1}{27}}{\frac{45}{27}+\frac{15}{27}-\frac{5}{27}}=\frac{\frac{9+3-1}{27}}{\frac{45+15-5}{27}}=\frac{\frac{11}{27}}{\frac{55}{27}}=\frac{11}{55}=\frac{1}{5}.\)
a) 1/2 + 3/4 - (3/4 - 4 - 5)
= 1/2 + 3/4 - 3/4 + 4 + 5
= (3/4 - 3/4) + (4 + 5) + 1/2
= 0 + 9 + 1/2
= 19/2
b) [9/16 + 8/(-27)] - (19/27- 7/16 - 2)
= 9/16 - 8/27 - 19/27 + 7/16 + 2
= (9/16 + 7/16) + (-8/27 - 19/27) + 2
= 1 - 1 + 2
= 2
c) -5/8 . [4/9 + 7/(-12)]
= -5/8 . (-5/36)
= 25/288
d) 7/10 . (-3/5) + 7/10 . (-2/5) - (-3/10)
= 7/10 . (-3/5 - 2/5) + 3/10
= 7/10 . (-1) + 3/10
= -2/5
e) -3/7 . 5/9 + 4/9 . (-3/7) + 2 3/7
= -3/7 . (5/9 + 4/9) + 17/7
= -3/7 . 1 + 17/7
= 2
f) 8 2/7 - (3 4/9 + 4 2/7)
= 8 + 2/7 - 3 - 4/9 - 4 - 2/7
= (8 - 3 - 4) + (2/7 - 2/7) - 4/9
= 1 - 4/9
= 5/9
h) 3.(-1/2)² - (4/5 + 8/15) : 5/6
= 3.1/4 - 4/3 : 5/6
= 3/4 - 8/5
= -17/20
Đặt A = \(\dfrac{5}{3}+\dfrac{5}{9}+\dfrac{5}{27}+...+\dfrac{5}{218}\)
\(\dfrac{A}{3}=\dfrac{5}{9}+\dfrac{5}{27}+\dfrac{5}{81}+...+\dfrac{5}{654}\)
\(A-\dfrac{A}{3}=\left(\dfrac{5}{3}+\dfrac{5}{9}+\dfrac{5}{27}+...+\dfrac{5}{218}\right)-\left(\dfrac{5}{9}+\dfrac{5}{27}+\dfrac{5}{81}+...+\dfrac{5}{654}\right)\)
\(\dfrac{2A}{3}=\dfrac{5}{218}-\dfrac{5}{654}\)
\(\dfrac{2A}{3}=\dfrac{5}{327}\)
\(2A=\dfrac{5}{327}\cdot3\)
\(2A=\dfrac{5}{109}\)
\(A=\dfrac{5}{109}:2\)
\(A=\dfrac{5}{218}\)
đề bài đâu