288/72=.../24=16/...=.../18
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đố mẹo hả
nếu đố mẹo thì bằng 288
còn kết quả bình thường thì ra là 8640
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\(\dfrac{1}{9x-18}+\dfrac{16-7x}{72-18x}+\dfrac{5}{12x+24}\)
=\(\dfrac{\left(72-18x\right)\left(12x+24\right)}{\left(9x-18\right)\left(72-18x\right)\left(12x+24\right)}+\dfrac{\left(16-7x\right)\left(9x-18\right)\left(12x+24\right)}{\left(72-18x\right)\left(9x-18\right)\left(12x+24\right)}+\dfrac{5\left(9x-18\right)\left(72-18x\right)}{\left(12x+24\right)\left(9x-18\right)\left(72-18x\right)}\)
=\(\dfrac{\left(72-18x\right)\left(12x+24\right)+\left(16-7x\right)\left(9x-18\right)\left(12x+24\right)+5\left(9x-18\right)\left(72-18x\right)}{\left(9x-18\right)\left(72-18x\right)\left(12x+24\right)}\)
=\(\dfrac{-756x^3+702x^2+8316x-11664}{\left(9x-18\right)\left(72-18x\right)\left(12x+24\right)}\)
=
Ngô thừa ân cái đề nhìn rối quá bạn ơi , có thể viết rõ ra hơn được không !
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\(\frac{20042004\cdot2006}{20062006\cdot2006}=\frac{2004\cdot10001\cdot2006}{2006\cdot10001\cdot2006}=\frac{1002.1.1}{1003.1.1}=\frac{1002}{1003}\)
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\(a.\dfrac{1}{a+1}+\dfrac{2}{1-a}+\dfrac{5a-1}{a^2-1}\)
\(=\dfrac{1}{a+1}-\dfrac{2}{a-1}+\dfrac{5a-1}{a^2-1}\)
\(=\dfrac{a-1}{\left(a+1\right)\left(a-1\right)}-\dfrac{2\left(a+1\right)}{\left(a+1\right)\left(a-1\right)}+\dfrac{5a-1}{\left(a+1\right)\left(a-1\right)}\)
\(=\dfrac{a-1-2a-2+5a-1}{\left(a+1\right)\left(a-1\right)}\)
\(=\dfrac{4a-4}{\left(a+1\right)\left(a-1\right)}\)
\(=\dfrac{4}{a+1}\)
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7/9 = 35/45 = 140/180 = 77/99
288/72 = 96/24 = 16/4 = 112/18
k đúng cho mình nha bn
\(\frac{7}{9}\)=\(\frac{35}{45}\)=\(\frac{140}{180}\)=\(\frac{77}{99}\)
\(\frac{288}{72}\)=\(\frac{96}{24}\)=\(\frac{16}{4}\)=\(\frac{112}{18}\)
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\(\dfrac{12+24+72}{18+36+108}=\dfrac{108}{162}=\dfrac{2}{3}=\dfrac{12}{18}=\dfrac{36}{54}\)
\(\dfrac{12-24+72}{18-36+108}=\dfrac{60}{90}=\dfrac{2}{3}=\dfrac{12}{18}=\dfrac{36}{54}\)
\(\dfrac{288}{72}=\dfrac{96}{24}=\dfrac{16}{4}=\dfrac{72}{18}\)
Ta có :
\(\dfrac{288}{72}=\dfrac{96}{24}=\dfrac{64}{16}=\dfrac{72}{18}\)