1/6 + 1/30 + 1/70 + 1/126 + ... + 1/966
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
=>2A=4/2*6+4/6*10+4/10*14+...+4/42*46
=>2A=1/2-1/6+1/6-1/10+...+1/42-1/46=1/2-1/46=22/46
=>A=11/46
\(A=\dfrac{1}{6}+\dfrac{1}{30}+\dfrac{1}{70}+\dfrac{1}{126}+...+\dfrac{1}{966}\)
\(\Rightarrow\dfrac{4}{2}A=\dfrac{4}{2}\cdot\left(\dfrac{1}{6}+\dfrac{1}{30}+\dfrac{1}{70}+...+\dfrac{1}{966}\right)\)
\(\Rightarrow2A=\dfrac{4}{2\times6}+\dfrac{4}{6\times10}+\dfrac{4}{10\times14}+\dfrac{4}{14\times18}+...+\dfrac{4}{42\times46}\)
\(\Rightarrow2A=\dfrac{1}{2}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{18}+...+\dfrac{1}{42}-\dfrac{1}{46}\)
\(\Rightarrow2A=\dfrac{1}{2}-\dfrac{1}{46}\)
\(\Rightarrow2A=\dfrac{11}{23}\)
\(\Rightarrow A=\dfrac{11}{23}:2\)
\(\Rightarrow A=\dfrac{11}{46}\)
Đặt A=\(\frac{1}{15}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}+\frac{1}{340}\)
Ta có:
A=\(\frac{1}{15}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}+\frac{1}{340}\)
=>A=\(\frac{1}{3.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\)
=\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+\frac{1}{17}-\frac{1}{20}\)
=\(\frac{1}{3}-\frac{1}{20}\)
=\(\frac{17}{60}\)
Câu b bạn đặt B bằng từng đó rồi nhân 2B lên và phân tách rồi giãn ước 6=1.6,60=6.10,140=10.140,v.v
Tính được kết quả thì chia 2
Câu hỏi của Thịnh - Toán lớp 6 - Học toán với OnlineMath
Bạn tham khảo câu hỏi ở link này.
1) \(1+\frac{1}{3}+1\frac{91}{27}+\frac{1}{81}\)
\(=1+\frac{1}{3}+4+\frac{10}{27}+\frac{1}{81}\)
\(=\left(1+4\right)+\left(\frac{1}{3}+\frac{10}{27}+\frac{1}{81}\right)\)
\(=5+\frac{58}{81}=5\frac{58}{81}\)
2) \(\frac{1}{78}+\frac{1}{91}+\frac{1}{105}+\frac{1}{120}+\frac{1}{136}\)
\(=\frac{1}{6\times13}+\frac{1}{13\times7}+\frac{1}{7\times15}+\frac{1}{15\times8}+\frac{1}{8\times17}\)
\(=\frac{1}{6}-\frac{1}{13}+\frac{1}{13}-\frac{1}{7}+\frac{1}{7}-\frac{1}{15}+\frac{1}{15}-\frac{1}{8}+\frac{1}{8}-\frac{1}{17}\)
(gạch bỏ các số giống nhau)
\(=\frac{1}{6}-\frac{1}{17}=\frac{11}{102}\)
3) \(\frac{1}{6}+\frac{1}{30}+\frac{1}{70}+\frac{1}{126}\)
\(=\frac{1}{2\times3}+\frac{1}{3\times10}+\frac{1}{10\times7}+\frac{1}{7\times18}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{10}+\frac{1}{10}-\frac{1}{7}+\frac{1}{7}-\frac{1}{18}\)
\(=\frac{1}{2}-\frac{1}{18}=\frac{4}{9}\)
chúc bn học tốt!!
công chúa ôri ơi mk viết nhầm đề bài 1
đề bài là 1+1/3+1/9+1/27+1/81
bạn trả lời giúp mk với mk cần gấp lắm
cảm ơn
Đề lỗi. mk sửa 15->10
\(\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}+\frac{1}{340}\)
\(=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\)
\(=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\)
\(=\frac{1}{3}\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{17.20}\right)\)
\(=\frac{1}{3}\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}\right)\)
\(=\frac{1}{3}\left(\frac{1}{2}-\frac{1}{20}\right)\)
\(=\frac{1}{3}.\frac{9}{20}\)
\(=\frac{9}{60}\)
Đặt \(S=\frac{1}{6}+\frac{1}{30}+\frac{1}{70}+\frac{1}{126}+\frac{1}{198}+\frac{1}{286}\)
\(\Leftrightarrow2S=\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}\)
\(\Leftrightarrow2S=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+\frac{1}{11.13}\)
\(\Leftrightarrow4S=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\)
\(\Leftrightarrow4S=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\)
\(\Leftrightarrow4S=1-\frac{1}{13}\)
\(\Leftrightarrow4S=\frac{12}{13}\)
\(\Leftrightarrow S=\frac{12}{13}\div4\)
\(\Leftrightarrow S=\frac{3}{13}\)
a) 123,45 x 678 - 246,9 x 338 - 246
= 83699,1 - 83452,2 - 246
= 246,9 - 246
= 0,9
b, \(\frac{1}{6}+\frac{1}{11}+\frac{1}{70}+\frac{1}{126}+\frac{1}{198}+\frac{1}{286}\)
Bạn tính ra máy tính bỏ túi
3A=2.33+6.33+12.31+20.33+30.33+42.33
3A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}3A=1.21+2.31+3.41+4.51+5.61+6.71
3A=\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{7-6}{6.7}3A=1.22−1+2.33−2+3.44−3+...+6.77−6
3A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}3A=1−21+21−31+31−41+...+61−71
3A=1-\frac{1}{7}=\frac{6}{7}\Rightarrow A=\frac{2}{7}3A=1−71=76⇒A=72