5^2.125.(2,5)^-5.0,04
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\(\frac{\left(-5\right)^2.20^4}{8^2.125}=\frac{25.20^4}{8^2.25.5}=\frac{20^4}{8^2.5}=500\)
a,-3/5.2/7+-3/7.3/5+-3/7
=-3/7.2/5+(-3/7).3/5+(-3/7)
=-3/7(2/5+3/5+1)
=-3/7.2
=-6/7
\(\dfrac{\left(-5\right)^2.20^2}{8^2.125}=\dfrac{\left[\left(-5\right).20\right]^2}{2^{3^2}.5^3}=\dfrac{\left(-100\right)^2}{\text{4^3}.5^3}=\dfrac{10000}{\left(4.5\right)^3}=\dfrac{10000}{20^3}\dfrac{10000}{8000}=\dfrac{5}{4}\)
2.25.9 + {[ 2.125 - ( 5x + 4 ).5 ] : ( 4.3.5 )]} = 453
= 2.25.9 + 250 - ( 5x + 4 ).5 ] : 12.5 = 453
= 50.9 + [ 250 - ( 5x + 4 ).5 ] : 60 = 453
= 450 + 250 - ( 5x + 4 ).5 = 453.60
= 450 + 250 - ( 5x + 4 ) = 453 : 5
= 450 + 250 - ( 5x + 4 ) = 90,6
= 450 + 250 - 5x = 90,6 - 4
= 450 + 250 - 5x = 86,6
= 700 - 5x = 86,6
= 86,6 + 700
= 5x = 786,6
= 786,6 : 5
= 157,32
2.25.9 + {[ 2.125 - ( 5x + 4 ).5 ] : ( 4.3.5 )]} = 453
= 2.25.9 + 250 - ( 5x + 4 ).5 ] : 12.5 = 453
= 50.9 + [ 250 - ( 5x + 4 ).5 ] : 60 = 453
= 450 + 250 - ( 5x + 4 ).5 = 453.60
= 450 + 250 - ( 5x + 4 ) = 453 : 5
= 450 + 250 - ( 5x + 4 ) = 90,6
= 450 + 250 - 5x = 90,6 - 4
= 450 + 250 - 5x = 86,6
= 700 - 5x = 86,6
= 86,6 + 700
= 5x = 786,6
= 786,6 : 5
= 157,32
Answer : 157,32
có
(-5)^2*20^4/862*125
=25*(4*5)^4/64*125
=25*4^4*5^4/64*125
=25*5*4^3*4*5^3/64*125
=125*64*4*5^3/64*125
=4*5^3
=500
\(8.25.29.2^2.125=\left(8.25\right).\left(2^2.125\right).29=200.500.29=2900000\)
\(=\left(8.125\right).\left(2^2.25\right).29=1000.100.29=2900000\)
\(9^3.\frac{25^3}{18^2}.125^2\)
<=>\(729.\frac{15625}{324}.15625\)
<=>\(\frac{140625}{4}.15625\)
\(\approx\)\(549316406\)
KQ ko đẹp lắm =((
\(\dfrac{25^2.125^2}{625^5}=\dfrac{5^4.5^6}{5^{20}}=\dfrac{5^{10}}{5^{20}}=\dfrac{1}{5^{10}}.\)
\(\dfrac{25^2.125^2}{625^5}=\dfrac{\left(5^2\right)^2.\left(5^3\right)^2}{\left(5^4\right)^5}\) \(=\dfrac{5^4.5^6}{5^{20}}\)=\(\dfrac{5^{10}}{5^{20}}\) = \(5^{-5}\)=\(\dfrac{1}{9765626}\)
52.125.(2,5)-5.0,04
=52.53.\(\dfrac{32}{3125}\).\(\dfrac{4}{100}\)
=55.\(\dfrac{32}{5^5}\).\(\dfrac{1}{25}\)
= \(\dfrac{32}{25}\)
32/25