Question

[Bich]

  Giải hộ mình lun với ạ !

Answer 1

[Akai Haruma]

1a.

$3+\sqrt{3}=\sqrt{3}.\sqrt{3}+\sqrt{3}=\sqrt{3}(\sqrt{3}+1)$

1b.

4+5\sqrt{2}=2\sqrt{2}.\sqrt{2}+5\sqrt{2}=\sqrt{2}(2\sqrt{2}+5)$

1c.

$6x-\sqrt{x}-1=(6x-3\sqrt{x})+(2\sqrt{x}-1)$

$=3\sqrt{x}(2\sqrt{x}-1)+(2\sqrt{x}-1)=(2\sqrt{x}-1)(3\sqrt{x}+1)$

Answer 2

[Akai Haruma]

1d.

$4x-3\sqrt{x}-1=(4x-4\sqrt{x})+(\sqrt{x}-1)$

$=4\sqrt{x}(\sqrt{x}-1)+(\sqrt{x}-1)=(\sqrt{x}-1)(4\sqrt{x}+1)$

1e.

$5x+3\sqrt{xy}-8y=(5x-5\sqrt{xy})+(8\sqrt{xy}-8y)$

$=5\sqrt{x}(\sqrt{x}-\sqrt{y})+8\sqrt{y}(\sqrt{x}-\sqrt{y})$

$=(\sqrt{x}-\sqrt{y})(5\sqrt{x}+8\sqrt{y})$

1g.

$3a-2\sqrt{ab}-b=(3a-3\sqrt{ab})+(\sqrt{ab}-b)$

$=3\sqrt{a}(\sqrt{a}-\sqrt{b})+\sqrt{b}(\sqrt{a}-\sqrt{b})$

$=(\sqrt{a}-\sqrt{b})(3\sqrt{a}+\sqrt{b})$