200.8*11.45-200.8*11.44
200.9*13.09-2009*13.08
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\(=\dfrac{\left(200.7-0.1\right)\left(200.7+0.1\right)+0.01}{200.7^2}\)
\(=\dfrac{200.7^2-0.01+0.01}{200.7^2}=\dfrac{200.7^2}{200.7^2}\)
=1
a.120-[7.20-(134-110).5]
=120-(7.20-24.5)
=120-(140-120)
=120-20
=100
b.1987-200.8+1005:5
=1987-1600+201
=588
C, 387.2694+7305.387+387
=387.(2694+7305+1)
=387.10000
3870 000
d,
d.248:{[(368+232):120-3]+122}+2016
=248:{(600:120-3)+122}+2016
=248:(2+122)+2016
=248:144+2016
=2+2016
=2018
a)120-[7.20-(134-110).5]
=120-20
=100
b)1987-200.8+1005:5
=1987-1600+201
=588
c)387.2694+7305.387+387
=1042578+2827035+387
=3870000
d)248:{[368+232):120-3]+122}+2016
=248:124+2016
=2+2016
=2018
a)120-[7.20-(134-110).5]
=120-20
=100
b)1987-200.8+1005:5
=1987-1600+201
=588
c)387.2694+7305.387+387
=1042578+2827035+387
=3870000
d)248:{[368+232):120-3]+122}+2016
=248:124+2016
=2+2016
=2018
`@` `\text {Ans}`
`\downarrow`
`-75.57 + 75.34 - ( 57.34 - 57.75 )`
`= -75 . 57 + 75.34 - 57.34 + 57.75`
`= 75.( - 57 + 34 + 57) + 75.34`
`= 75.34 + 75.34`
`= (75.34) .2`
`= 2550 . 2`
`= 5100`
_______
\(-11.45 - (-11).25 - ( 29.3+29.17 )\)
`= -11. (45 - 25) - 29(3 + 17)`
`= -11.20 - 29.20`
`= 20. (-11 - 29)`
`= 20. (-40)`
`= -80`
_______
\(-12.7 -72.(-12) - ( 25.55-25.43 )\)
`= -12. (7 - 72) - 25( 55 - 43)`
`= -12.(-65) - 25.12`
`= 12.65 - 25 . 12`
`= 12(65 - 25)`
`= 12.40`
`= 480`
One day as any other day. Nga gets up at 5.45 and has breakfast at 6 o'clock. Thirty minutes later, she leaves house for school. Her school starts at 7.00 and ends at 11.15. After stuyding at school, she goes home and has lunch at 11.45. In the afternoon, she does her homework and listens to music. From 4 to 5pm, she goes out to play sports. She has dinner with her family at 6pm. In the evening, she does her homework again and watches TV. She goes to bed at 10.45. One day... as any other day
200.8*11.45-200.8*11.44
= (200.8*11.45)-(200.8*11.44)
= 2299,16 - 2297,152
= 2008
200.9*13.09-200.9*13.08
= (200.9*13.09)-(200.9*13.08)
= 2629,781 - 2627,772
= 2009