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10 tháng 8 2022

\(\dfrac{7}{15}.\left[\left(-\dfrac{3}{8}\right)-\dfrac{3}{7}\right]\)

\(=\dfrac{7}{15}.-\dfrac{45}{56}\)

\(=-\dfrac{315}{840}\)

10 tháng 8 2022

7/15.[(-3/8)-3/7]

= 7/15 . ( -45/56 )

= -3/8 

17 tháng 4 2019

a)\(\frac{-3}{8}.\frac{2}{5}+\frac{-3}{8}.\frac{14}{5}\)

\(=\frac{-3}{8}.\left(\frac{2}{5}+\frac{14}{5}\right)\)

\(=\frac{-3}{8}.\frac{16}{5}\)

\(=\frac{-6}{5}\)

17 tháng 4 2019

a, =-3/8.(2/5+14/5)

    =-3/8.16/5

   =-6/5

b, =3/2.7/2+-11/15:11/30

    =21/4+-2

    =13/4

2:

a: \(=\dfrac{1}{3}\left(-\dfrac{4}{5}-\dfrac{6}{5}\right)=-\dfrac{1}{3}\cdot2=-\dfrac{2}{3}\)

1:

\(A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)

\(=-4-\dfrac{1}{4}=-\dfrac{17}{4}\)

8 tháng 10 2023

Bài 1:

\(A=\left(7-\dfrac{3}{4}+\dfrac{1}{3}\right)-\left(6+\dfrac{5}{4}-\dfrac{4}{3}\right)-\left(5-\dfrac{7}{4}+\dfrac{5}{3}\right)\)

\(A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)

\(A=\left(7-6-5\right)-\left(\dfrac{3}{4}+\dfrac{5}{4}-\dfrac{7}{4}\right)+\left(\dfrac{1}{3}+\dfrac{4}{3}-\dfrac{5}{3}\right)\)

\(A=-4-\dfrac{3+5-7}{4}+\dfrac{1+4-5}{3}\)

\(A=-4-\dfrac{1}{4}+\dfrac{0}{3}\)

\(A=-\dfrac{16}{4}-\dfrac{1}{4}+0\)

\(A=\dfrac{-16-1}{4}\)

\(A=-\dfrac{17}{4}\)

Bài 2:

\(\dfrac{1}{3}\cdot-\dfrac{4}{5}+\dfrac{1}{3}\cdot-\dfrac{6}{5}\)

\(=\dfrac{1}{3}\cdot\left(-\dfrac{4}{5}-\dfrac{6}{5}\right)\)

\(=\dfrac{1}{3}\cdot\dfrac{-4-6}{5}\)

\(=\dfrac{1}{3}\cdot\dfrac{-10}{5}\)

\(=\dfrac{1}{3}\cdot-2\)

\(=-\dfrac{2}{3}\)

16 tháng 3 2020

Làm 1 câu

10/3...>...1/3

Mấy câu ssu tự quy đồng hay gì gì đấy!

16 tháng 3 2020

10/3.>..1/3.     10/6.>..3/8.     17/4.>..5/6.    1/3..<.5/9     5/8.<..7/5    3/4..<.15/6      10/9.>..10/11   7/8..<.7/2       15/9.>..3/8  15/7.>..15/8      16/5.>..16/7    25/11..<.1

a: =1/8-1/8+2/5=2/5

b: =(-1/15-14/15)+(23/27+31/27)=2-1=1

c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)

d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)

18 tháng 5 2019

Ta có: \(D=\dfrac{3}{7}\left(\dfrac{13}{-8}-\dfrac{7}{9}\right)-\dfrac{5}{8}\left(\dfrac{3}{7}-\dfrac{-8}{15}\right)\)

\(=\dfrac{3}{7}\cdot\dfrac{-13}{8}-\dfrac{3}{7}\cdot\dfrac{7}{9}-\dfrac{5}{8}\cdot\dfrac{3}{7}-\dfrac{5}{8}\cdot\dfrac{8}{15}\)

\(=\dfrac{-39}{56}-\dfrac{3}{7}\left(\dfrac{7}{9}+\dfrac{5}{8}\right)-\dfrac{1}{3}\)

\(=\dfrac{-137}{84}\)

\(D=\dfrac{3}{7}(\dfrac{13}{-8}-\dfrac{7}{9})-\dfrac{5}{8}(\dfrac{3}{7}-\dfrac{-8}{15})\)

\(=(\dfrac{3}{7}. \dfrac{101}{105}).(\dfrac{-173}{72}-\dfrac{5}{8})\)

\(=\dfrac{101}{245}.\dfrac{-109}{36}\)

\(=\dfrac{593}{4410}\)