Bài toán lớp 6 f)(-3)+4+36+(-17)
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- 3/12;6/24
- 3737/9999=373737/999999=37373737/99999999 vì chúng đều = 37/99.
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\(\frac{9}{22}\times\frac{33}{18}=\frac{9\times3\times11}{2\times11\times9\times2}\)\(=\frac{3}{4}\)
\(\frac{12}{35}:\frac{36}{25}=\frac{12}{35}\times\frac{25}{36}\)\(=\frac{12\times5\times5}{5\times7\times12\times3}=\)\(\frac{5}{21}\)
\(\frac{10}{17}:\frac{76}{51}=\frac{10}{17}\times\frac{51}{76}\)\(=\frac{10\times3\times17}{17\times76}\)\(=\frac{30}{76}=\frac{15}{38}\)
a,\(\frac{3}{4}\)
b,\(\frac{5}{21}\)
c,\(\frac{15}{38}\)
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\(a,210-5x=200\)
\(5x=10\)
\(x=2\)
Vậy \(x=2\)
\(b,210-5\left(x-10\right)=200\)
\(5\left(x-10\right)=10\)
\(x-10=2\)
\(x=12\)
Vậy \(x=12\)
\(c,450\div\left[41-\left(2x-5\right)\right]=3^2.5\)
\(450\div\left[41-\left(2x-5\right)\right]=45\)
\(41-\left(2x-5\right)=10\)
\(2x-5=31\)
\(2x=36\)
\(x=18\)
Vậy \(x=18\)
\(d,350\div x+10=20\)
\(350\div x=10\)
\(x=35\)
Vậy \(x=35\)
\(e,36\div\left(x-5\right)=2^2\)
\(36\div\left(x-5\right)=4\)
\(x-5=9\)
\(x=14\)
Vậy \(x=14\)
\(f,\left[3\left(70-x\right)+5\right]\div2=46\)
\(3\left(70-x\right)+5=92\)
\(3\left(70-x\right)=87\)
\(70-x=29\)
\(x=41\)
Vậy \(x=41\)
a)210-5x=200 b)210-5(x-10)=200
5x=210-200=10 5(x-10)=210-200=10
x=10:5=2 x-10 =10:5=2 c)45:[41-(2x-5)]=32.5 x =2+10=12
45:[41-(2x-5)] =9.5=45 d)350:x+10=20
41-(2x-5)=45:45=1 350:x =20-10=10
2x-5 =41-1=40 x =350:10=35
2x =40+5=45
x =45:2=22,5
e)36:(x-5)=22 f)[3.(70-x)+5]:2=46
36:(x-5)=4 [3.(70-x)+5] =46.2=92
x-5 =36:4=9 3.(70-x) =92-5=87
x =9+5=14 70-x =87:3=29
x =70-29=41
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đi tui cần điểm hỏi đáp
(-3) + 4 + 36 + (-17)
= [(-3) + (-17)] + (4 + 36)
= -20 + 40
= 20
(-3) + 4 + 36 + (-17)
= [(-3) + (-17)] + (4 + 36)
= -20 + 40
= 20