- Tìm x
18x – 2x – 4x – 24 = 36
Ai giúp e bai toán này đi ạ.E cần gấp lém.Thank m.n trước❤️
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Đỗ Thanh Hải
CTVVIP
28 tháng 4 2021
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18 tháng 9 2023
a) \(\dfrac{x^3-1}{x^2+x+1}=\dfrac{\left(x-1\right)\left(x^2+x+1\right)}{x^2+x+1}=x-1\)
b) \(\dfrac{x^2+2xy+y^2}{2x^2+xy-y^2}\)
\(=\dfrac{\left(x+y\right)^2}{x^2+xy+x^2-y^2}=\dfrac{\left(x+y\right)^2}{x\left(x+y\right)+\left(x-y\right)\left(x+y\right)}\)
\(=\dfrac{\left(x+y\right)^2}{\left(2x-y\right)\left(x+y\right)}=\dfrac{x+y}{\left(2x-y\right)}\)
c) \(\dfrac{ax^4-a^4x}{a^2+ax+x^2}\)
\(=\dfrac{ax\left(x^3-a^3\right)}{a^2+ax+x^2}\)
\(=\dfrac{ax\left(x-a\right)\left(a^2+ax+x^2\right)}{a^2+ax+x^2}\)
\(=ax\left(x-a\right)\)
\(18x-2x-4x-24=36\)
\(12x=36+24\)
\(12x=60\)
\(x=60:12\)
\(x=5\)
18x-2x-4x-24=36
<=>12x-24=36
<=>12x=60
<=>x=5