Tính 1x3x5+2x6x10+3x9x15/3x5x12+6x10x24+9x15x36
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A = \(\dfrac{1\times3\times5+2\times6\times10+3\times9\times15}{3\times5\times12+6\times10\times24+9\times15\times36}\)
A = \(\dfrac{1\times3\times5+2\times6\times10+3\times9\times15}{3\times5\times12+6\times10\times2\times12+9\times15\times3\times12}\)
A = \(\dfrac{1\times3\times5+2\times6\times10+3\times9\times15}{12\times\left(1\times3\times5+6\times10\times2+9\times15\times3\right)}\)
A = \(\dfrac{1\times3\times5+2\times6\times10+3\times9\times15}{12\times\left(1\times3\times5+2\times6\times10+3\times9\times15\right)}\)
A = \(\dfrac{1}{12}\)
A = 1×3×5+2×6×10+3×9×153×5×12+6×10×24+9×15×36
A = 1×3×5+2×6×10+3×9×153×5×12+6×10×2×12+9×15×3×12
A = 1×3×5+2×6×10+3×9×1512×(1×3×5+6×10×2+9×15×3)
A = 1×3×5+2×6×10+3×9×1512×(1×3×5+2×6×10+3×9×15)
A = 112
\(\dfrac{1\times2\times3+2\times4\times6+4\times8\times12+7\times14\times21}{1\times3\times5+2\times6\times10+4\times12\times20+7\times21\times35}\\ =\dfrac{1\times2\times3}{1\times3\times5}+\dfrac{2\times4\times6}{2\times6\times10}+\dfrac{4\times8\times12}{4\times12\times20}+\dfrac{7\times14\times21}{7\times21\times35}\\ =\dfrac{2}{5}+\dfrac{4}{10}+\dfrac{8}{20}+\dfrac{14}{35}\\ =\dfrac{2}{5}+\dfrac{2}{5}+\dfrac{2}{5}+\dfrac{2}{5}\\ =\dfrac{2}{5}\times4\\ =\dfrac{8}{5}\)
1X3X5+2X6X10+4X12X20+7X21X35 /1X5X7+2X10X14+4X20X28+7X35X49
=3+6+12+21 /7+14+28+49
=42 /98=3/7
Bài này chỉ có thể tính bình thường đc thôi ak, nếu muốn lời giải chuẩn thì tham khảo nhé!
\(\frac{1x3x5+2x6x10+4x12x20+7x21x35}{1x5x7+2x10x14+4x20x28+7x35x49}\)
Nhận xét:
a)Phần tử số:
2x6x10= (1 x 2) x (3x2) x (5x2) = (2x2x2) x (1x3x5)
4x12x20= (1x4) x (3x4) x (5x4) = (4x4x4) x (1x3x5)
7x21x35= (1x7) x (3x7) x (5x7) = (7x7x7) x (1x3x5)
b)Phần mẫu số:
2x10x14= (1x2) x (5x2) x (7x2) = (2x2x2) x (1x5x7)
4x20x28= (1x4) x (5x4) x (7x4) = (4x4x4) x (1x5x7)
7x35x49= (1x7) x (5x7) x (7x7) = (7x7x7) x (1x5x7)
Vậy:
\(\frac{1x3x5+2x6x10+4x12x20+7x21x35}{1x5x7+2x10x14+4x20x28+7x35x49}\)
\(=\frac{\left(1x3x5\right)+\left(2x2x2\right)x\left(1x3x5\right)+\left(4x4x4\right)x\left(1x3x5\right)+\left(7x7x7\right)x\left(1x3x5\right)}{\left(1x5x7\right)+\left(2x2x2\right)x\left(1x5x7\right)+\left(4x4x4\right)x\left(1x5x7\right)+\left(7x7x7\right)x\left(1x5x7\right)}\)
\(=\frac{\left(1x3x5\right)x\left(1+2x2x2+4x4x4+7x7x7\right)}{\left(1x5x7\right)x\left(1+2x2x2+4x4x4+7x7x7\right)}\)
\(=\frac{1x3x5}{1x5x7}\)\(=\frac{3}{7}\)
Ta có:
\(A=\frac{1x5x6+2x10x12+4x20x24+9x45x54}{1x3x5+2x6x10+4x12x20+9x27x45}\)
\(=\frac{1x3x5x2+2x6x10x2+4x12x20x2+9x27x45x2}{1x3x5+2x6x10+4x12x20+9x27x45}\)
\(=\frac{\left(x3x5+2x6x10+4x12x20+9x27x45\right)x2}{x3x5+2x6x10+4x12x20+9x27x45}\)
\(=2\)
\(A=\frac{1x5x6+1.2x2.5x2.6+1.4x4.5x6.4+1.9x5.9x6.9}{1x3x5+1.2x3.2x2.5+1.4x3.4x5.4+1.7x3.3x5.9}\)
\(A=\frac{1x5x6\left(1+2.2.2+4.4.4+9.9.9\right)}{1x3x5\left(1+2.2.2+4.4.4+7.3.9\right)}\)
\(A=\frac{1x5x6.802}{1x3x5.262}\)\(A=\frac{1x5x6.2.401}{1x3x5.2.131}\)
còn đâu cậu tự làm
\(A=\frac{1x5x6+2x1x2x5x2x6+8x1x2x5x4x6}{1x3x5+2x1x2x3x2x5+8x1x2x3x4x5}\)
\(A=\frac{1x5x6+2x2x2x1x5x6+8x2x4x1x5x6}{1x3x5+2x2x2x1x3x5+8x2x4x1x3x5}\)
\(A=\frac{1x5x6x\left(1+2x2x2+8x2x4\right)}{1x3x5x\left(1+2x2x2+8x2x4\right)}=\frac{6}{3}=2\)
\(\dfrac{1x3x5+2x6x10+3x9x15}{3x5x12+6x10x24+9x15x36}=\)
\(=\dfrac{1x3x5+2x1x2x3x2x5+3x1x3x3x3x5}{3x5x12+2x3x2x5x2x12+3x3x3x5x3x12}=\)
\(\dfrac{1x3x5x\left(1+2x2x2+3x3x3\right)}{3x5x12x\left(1+2x2x2+3x3x3\right)}=\dfrac{1}{12}\)