21^5 : 81^3
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\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26+12}{81}=\dfrac{38}{81}\)
\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5+56}{64}=\dfrac{61}{64}\)
\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26}{81}+\dfrac{4\times3}{27\times3}=\dfrac{26}{81}+\dfrac{12}{81}=\dfrac{38}{81}\)
\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5}{64}+\dfrac{7\times8}{8\times8}=\dfrac{5}{64}+\dfrac{56}{64}=\dfrac{61}{64}\)
\(21^5:81^3=\left(7.3\right)^5:\left(3^4\right)^3=7^5.3^5:3^{12}=7^5.3^7\)
\(21^5\div81^3\)
\(=\)\(\left(7.3\right)^5\div\left(3^4\right)^3\)
\(=\)\(7^5.3^5\div3^{12}\)
\(=\)\(7^5.3^7\)
2/3 * 10/21 * 3/2 = (2/3 * 3/2) * 10/21 = 1 * 10/21 = 10/21
22/5 * 12 * 5/12 = 22/5 * (12 * 5/12) = 22/5 * 5 =22
7/2 * 28/81 * 2/7= (7/2 * 2/7) * 28/81 = 1 * 28/81 =28/81
5/17 * 21/4 * 47/15 * 0 = 0
~Study well~
#Seok_Jin#