tìm x :
32:[x:35]=56
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Câu 1: \(\frac{17}{51}\)x \(\frac{45}{30}\)= \(\frac{1}{3}\)x \(\frac{3}{2}\)
= \(\frac{1}{2}\).
Câu 2: \(\frac{24}{15}\)x \(\frac{56}{72}\)x \(\frac{10}{14}\)= \(\frac{8}{5}\)x \(\frac{7}{9}\)x \(\frac{5}{7}\)
= \(\frac{56}{45}\)x \(\frac{5}{7}\)
= \(\frac{8}{9}\)
Câu 3: \(\frac{32}{48}\times\frac{35}{21}\times\frac{63}{14}\times\frac{9}{30}=\frac{2}{3}\times\frac{5}{3}\times\frac{9}{2}\times\frac{3}{10}=\frac{3}{2}\)
k nha
a)17/51x45/40=1/3x3/2=3/6=1/2
b)24/15x56/72x10/14=8/5x7/9x5/7=8/9
c)32/48x35/21x63/14x9/30=2/3x5/3x9/2x3/10=3/2
Tìm x biết:
56 : 49 = (-32) : x
-> (-32) : x = 56 : 49
(-32) : x = \(\dfrac{8}{7}\)
x = \(\left(-32\right):\dfrac{8}{7}\)
x = -28
Ta có: \(56:49=-32:x\)
\(\Leftrightarrow-32:x=\dfrac{56}{49}=\dfrac{8}{7}\)
\(\Leftrightarrow x=-32:\dfrac{8}{7}=-32\cdot\dfrac{7}{8}=-28\)
Vậy: x=-28
1)\(\left(x-280\right):35=56.5\)
\(\left(x-280\right):35=280\)
\(x-280=280.35\)
\(x-280=9800\)
\(x=9800+280\)
\(x=10080\)
2) \(\left(x-128+20\right):192=0\)
\(\Rightarrow\left(x-148\right):192=0\)
\(\Rightarrow x-148=0\)
\(\Rightarrow x=0+148\)
\(\Rightarrow x=148\)
3) \(460+85.4=\left(x+200\right).4\)
\(\Rightarrow\left(x+200\right).4=460+340\)
\(\Rightarrow\left(x+200\right).4=800\)
\(\Rightarrow x+200=800:4=200\)
\(\Rightarrow x+200=200\)
\(\Rightarrow x=200-200=0\)
4) \(x+5.2-\left(32+16.3:16-15\right)=0\)
\(\Rightarrow x+10-\left(32+3-15\right)=0\)
\(\Rightarrow x+10-20=0\)
\(\Rightarrow x+10=20\)
\(\Rightarrow x=20-10=10\)
nha m.n
a) 17 + x=13
=> x=17-13
=> x=4
b) x-25=-18
=>x=-18+25
=>x=7
c) -32-x=-36
=>x=36-32
=> x=4
d) x+78=-56
=> x=-56-78
x=-134
a) \(17+x=13\)
\(\Rightarrow x=13-17\)
\(\Rightarrow x=-4\)
Vậy x = -4
b) \(x-25=-18\)
\(\Rightarrow x=-18+25\)
\(\Rightarrow x=7\) _ Vậy x = 7
c) \(-32-x=-36\)
\(\Rightarrow x=-32-\left(-36\right)\)
\(\Rightarrow x=4\)_Vậy x = 4
d) \(x+78=-56\)
\(\Rightarrow x=-56-78\)
\(\Rightarrow x=-134\)
Vậy x = -134
\(\frac{32}{\frac{x}{35}}\)=56 => 32.35:x=56 => 1120:x=56 =>x=20
**k nha!!