Tính nhanh:\(\frac{\frac{504\times85+50\%\times\left(-45\div9+7\right)^3+636\times\left(-56\right)-24\times\left(-301\right)}{2}}{-3,25\times\frac{4}{5}\times\left(-107,5\right)+87,5\times2600\%\div0,5}\)
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\(=\frac{1}{2}\times\frac{2}{3}\times....\times\frac{2003}{2004}\)
\(=\frac{1\times2\times3\times...\times2003}{2\times3\times4\times...\times2014}\)
\(=\frac{1}{2014}\)
1, =\(\frac{2\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}{4\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}=\frac{1}{2}\)
2, A=\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{99}{100}\)
= \(\frac{1\cdot2\cdot3\cdot....\cdot99}{2\cdot3\cdot4\cdot...\cdot100}=\frac{1}{100}\)
Vậy ......
hok tốt
= 3/2 + 4/3 + 5/4 ................................ 100/99
= 100/2 = 50
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{2002}{2003}\cdot\frac{2003}{2004}\)
\(=\frac{1\cdot2\cdot3\cdot....\cdot2002\cdot2003}{2\cdot3\cdot4\cdot5\cdot....\cdot2003\cdot2004}\)
\(=\frac{1}{2004}\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{2003}{2004}=\frac{1\cdot2\cdot3\cdot4....2003}{2\cdot3\cdot4\cdot5....2004}=\frac{1}{2004}\)
\(A=1+\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+...+\frac{1}{16}.\left(1+2+...+16\right)\)
\(=1+\frac{1}{2}.2.3:2+\frac{1}{3}.3.4:2+...+\frac{1}{16}.16.17:2=1+\frac{3}{2}+\frac{4}{2}+...+\frac{17}{2}=\frac{2+3+4+...+17}{2}=\frac{152}{2}=76\)
\(\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\frac{-3}{8}\)
\(=\left(-2.\frac{-7}{4}.\frac{-3}{8}\right).\frac{-38}{21}\)
\(=\left(\frac{7}{2}.\frac{-3}{8}\right).\frac{-38}{21}\)
\(=\frac{-21}{16}.\frac{-38}{21}\)
\(=\frac{-38}{-16}=\frac{19}{8}\)
\(\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\left(\frac{-3}{8}\right)\)
\(=\left(-2.\frac{-7}{2}.\frac{-3}{8}\right).\frac{-38}{21}\)
\(=\left(7.\frac{-3}{8}\right).\frac{-38}{21}\)
\(=\frac{-21}{8}.\frac{-38}{21}\)
\(=\frac{-38}{-8}=\frac{19}{4}\)
biết làm bài 1 thôi
\(\left(\frac{1}{2}+1\right)\times\left(\frac{1}{3}+1\right)\times\cdot\cdot\cdot\times\left(\frac{1}{999}+1\right)\)
= \(\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\cdot\cdot\cdot\times\frac{1000}{999}\)
lượt bỏ đi còn :
\(\frac{1000}{2}=500\)