(\(\frac{7}{8}\)-\(\frac{3}{4}\)).1\(\frac{1}{3}\)-\(\frac{2}{7}\).(3,5)2
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28 tháng 5 2020
1) \(\left(\frac{7}{8}-\frac{3}{4}\right).1\frac{1}{3}-\frac{2}{7}.\left(3,5\right)^2\)
= \(\frac{1}{8}.\frac{4}{3}-\frac{2}{7}.\frac{49}{4}\) = \(\frac{-10}{3}\)
2) \(\frac{5}{4}:\frac{1}{2}-\frac{3}{4}\) = \(\frac{7}{4}\)
13 tháng 6 2020
a, \(-1,8:\left(1-\frac{3}{4}\right)\)
\(=-\frac{9}{5}:\frac{1}{4}\)
\(=-\frac{36}{5}\)
b, \(\left(\frac{7}{8}-\frac{3}{4}\right)\cdot1\frac{1}{3}-\frac{2}{7}\cdot\left(3,5\right)^2\)
\(=\left(\frac{7}{8}-\frac{6}{8}\right)\cdot\frac{4}{3}-\frac{2}{7}\cdot12.25\)
\(=\frac{1}{8}\cdot\frac{4}{3}-\frac{2}{7}\cdot\frac{49}{4}\)
\(=\frac{1}{6}-\frac{7}{2}\)
\(=\frac{1}{6}-\frac{21}{6}\)
\(=-\frac{20}{6}\)
\(=-\frac{10}{3}\)
B
30 tháng 4 2019
\(\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\left(\frac{9}{24}+-\frac{18}{24}+\frac{14}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}.\frac{6}{5}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{2}{4}\)
\(=\frac{3}{4}\)
B
30 tháng 4 2019
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\left(\frac{15}{20}-\frac{16}{20}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\frac{-1}{20}\)
\(=\frac{10}{20}+\frac{15}{20}-\frac{-1}{20}\)
\(=\frac{25}{20}-\frac{-1}{20}\)
\(=\frac{26}{20}\)
\(=\frac{13}{10}\)
23 tháng 7 2020
\(x+3,5-\frac{4}{7}=\frac{3}{2}-5\frac{1}{8}\)
=> \(x+\frac{35}{10}-\frac{4}{7}=\frac{3}{2}-\frac{41}{8}\)
=> \(x+\frac{7}{2}-\frac{4}{7}=\frac{12}{8}-\frac{41}{8}\)
=> \(x+\frac{7}{2}-\frac{4}{7}=-\frac{29}{8}\)
=> \(x+\frac{7}{2}=-\frac{29}{8}+\frac{4}{7}=-\frac{171}{56}\)
=> \(x=-\frac{171}{56}-\frac{7}{2}=-\frac{367}{56}\)
23 tháng 7 2020
Trả lời:
\(x+3,5-\frac{4}{7}=\frac{3}{2}-5\frac{1}{8}\)
\(\Leftrightarrow x+\frac{7}{2}-\frac{4}{7}=\frac{3}{2}-\frac{41}{8}\)
\(\Leftrightarrow x+\frac{7}{2}-\frac{4}{7}=\frac{-29}{8}\)
\(\Leftrightarrow x+\frac{7}{2}=\frac{-171}{56}\)
\(\Leftrightarrow x=\frac{-367}{56}\)
Vậy \(x=\frac{-367}{56}\)
27 tháng 4 2019
Bài 2 :
1) \(x-70=-45\) 2) \(\frac{4}{7}:x=\frac{12}{28}\)
\(\Rightarrow\) \(x=-45+70\) \(\Rightarrow x=\frac{4}{7}:\frac{12}{28}\)
\(\Rightarrow\) \(x=25\) \(\Rightarrow x=\frac{4}{3}\)
Vậy \(x=25\) Vậy \(x=\frac{4}{3}\)
3) Giống câu c) ở bài 1
4) \(x-50=-35\) 5) \(\frac{4}{7}.x=\frac{11}{18}\)
\(\Rightarrow x=-35+50\) \(\Rightarrow x=\frac{11}{28}:\frac{4}{7}\)
\(\Rightarrow x=15\) \(\Rightarrow x=\frac{77}{72}\)
Vậy \(x=15\) Vậy \(x=\frac{77}{72}\)
6) \(\left(\frac{2}{3}x+2,5\right):2\frac{2}{6}=6\)
\(\Rightarrow\)\(\left(\frac{2}{3}x+2,5\right):\frac{14}{6}=6\)
\(\Rightarrow\) \(\frac{2}{3}x+2,5=6.\frac{14}{6}\)
\(\Rightarrow\frac{2}{3}x+2,5=14\)
\(\Rightarrow\frac{2}{3}x=\frac{23}{2}\)
\(\Rightarrow x=\frac{23}{2}:\frac{2}{3}\)
\(\Rightarrow x=\frac{69}{4}\)
Vậy \(x=\frac{69}{4}\)
27 tháng 4 2019
Bài 1:
1) \(\frac{7}{5}+\frac{-8}{5}=-\frac{1}{5}\)
2) \(-\frac{6}{5}.\frac{15}{24}=-\frac{3}{4}\)
3) \(\left(\frac{2}{3}+1,5\right)-3,5:7\frac{1}{2}=\)\(\frac{13}{6}-\frac{7}{15}=\frac{17}{10}\)
4) \(\frac{5}{8}-\frac{-7}{9}=\frac{5}{8}+\frac{7}{9}=\frac{101}{72}\)
5)\(\frac{-7}{3}.\frac{12}{28}=-1\)
GR
2 tháng 11 2017
\(a,\frac{-8}{15}.\left(-30\right).\frac{15}{-8}.\frac{9}{10}\)
\(=-\left(\frac{8}{15}.\frac{15}{8}\right).\left(30.\frac{9}{10}\right)\)
\(=-1.27
=-27\)
\(b,2\frac{1}{18}.\frac{23}{24}.\frac{9}{37}.\frac{48}{-15}\)
\(=\frac{-37.23.9.48}{18.24.37.15}=\frac{23}{15}\)
c, chịu rồi
(1/8).4/3-2/7.12,25
=1/6-7/2=-10/3
\(\left(\frac{7}{8}-\frac{3}{4}\right)\cdot1\frac{1}{3}-\frac{2}{7}\cdot\left(3,5\right)^2\)\(=\frac{1}{8}\cdot\frac{4}{3}-\frac{2}{7}\cdot12,25\)\(=\frac{1}{6}-3,5=\frac{1}{6}-\frac{7}{5}=\frac{-37}{30}\)