\(105^x.105^3=105^7\)
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\(105^5.105^6\div105^8-105^3+105^7\)
\(=105^{11}\div105^8-105^3+105^7\)
\(=105^3-105^3+105^7\)
\(=0+105^7\)
\(=105^7\)
458 x 105 + 324 x 105 + 217 x 105 +105
= 105 x ( 458 + 324 + 217 + 1 )
= 105 x 1000
= 105000
Đây bạn nhé. Nhớ k cho mk nha
\(\dfrac{3}{7}:\dfrac{7}{x}:\dfrac{3}{4}=\dfrac{12}{105}\)
\(\dfrac{3}{7}.\dfrac{x}{7}=\dfrac{3}{35}\)
\(\dfrac{x}{7}=\dfrac{1}{5}\)
\(x=\dfrac{1}{5}.7=\dfrac{7}{5}\)
tìm x biết :
\(\dfrac{3}{7}\) : \(\dfrac{7}{x}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{105}\)
\(\dfrac{3}{7}\) : \(\dfrac{7}{x}\) = \(\dfrac{12}{105}\)\(\times\) \(\dfrac{3}{4}\)
\(\dfrac{3}{7}\) \(\times\) \(\dfrac{x}{7}\) = \(\dfrac{3}{35}\)
\(\dfrac{x}{7}\) = \(\dfrac{3}{35}\) : \(\dfrac{3}{7}\)
\(\dfrac{x}{7}\) = \(\dfrac{1}{5}\)
\(x\) = \(\dfrac{1}{5}\) \(\times\) 7
\(x\) = \(\dfrac{7}{5}\)
\(a,12-\left(4+105-13\right)+\left(4+105-3\right)\)
\(=12-4-105+13+4+105-3\)
\(=12+\left(-4+4\right)+\left(-105+105\right)+\left(13-3\right)\)
\(=12+0+0+10\)
\(=22\)
\(b,-15+\left(-17+21-35\right)+\left(4+105-13\right)\)
\(=-15-17+21-35+4+105-13\)
\(=\left(-15-35\right)+\left(-17-13\right)+\left(21+4+105\right)\)
\(=-50-30+130\)
\(=-50+100\)
\(=50\)
\(c,\left(\left|-5\right|+\left|+7\right|+\left|-9\right|\right)-\left(\left|+5\right|+\left|-7\right|+9\right)\)
\(=\left(5+7+9\right)-\left(5+7+9\right)\)
\(=0\)
\(105^x.105^3=105^7\)
\(105^x=105^7:105^3\)
\(105^x=105^4\)
\(=>x=4\)
105x . 1053 = 1057
105x = 1057 - 1053
=> x = 7 - 3
x = 4