118 x 118 = ?
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\(=\dfrac{117}{18}\left(\dfrac{1}{6}+\dfrac{1}{3}+\dfrac{1}{2}\right)=\dfrac{117}{18}\)
a/ \(\left(x-35\right)-120=0\)
\(\Leftrightarrow x-35=0+120\)
\(\Leftrightarrow x-35=120\)
\(\Leftrightarrow x=120+35\)
\(\Leftrightarrow x=155\)
Vậy ...
b/ \(124+\left(188-x\right)=217\)
\(\Leftrightarrow188-x=217-124\)
\(\Leftrightarrow188-x=93\)
\(\Leftrightarrow x=95\)
Vậy ...
b/ \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
\(\Leftrightarrow x=13\)
Vậy ..
a) x + 118 = 218
x = 218 – 118
x = 100
b) 18 – x = -17
X = 18 – (-17)
X = 35
c) (-18) – x = -17
X = (-18) – (-17)
X = -1
d)124 + (118 – x) = 217
118 – x = 93
X = 118 – 93
X = 25
e) (3x – 6).3 = 34
(3x – 6).3 = 81
3x – 6 = 27
3x = 33
ð X = 11
g) 23.(42 – x) = 46
42 – x = 2
ð X = 40
h) 84 – (3x + 8) = 34
3x + 8 = 84 – 34
3x + 8 = 50
3x = 50 – 8
3x = 42
X = 42 : 3
ð X = 14
i) 3.(2x + 1) – 19 = 14
3.(2x + 1) = 14 + 19
3.(2x + 1) = 33
2x + 1 = 33 : 3
2x + 1 = 11
2x = 11 – 1
2x = 10
X = 10 : 2
ð X = 5
k) 6x – 302 = 23.5
6x – 302 = 40
6x = 40 + 302
6x = 342
X = 342 : 6
ð X = 57
m) (x – 1)2 = 81
(x – 1)2 = 92
ð X – 1 = 9
ð X = 9 + 1
ð X = 10
n) 2x+1 – 5 = 27
2x+1 = 27 + 5
2x+1 = 32
2x+1 = 25
ð X = 4
\(\dfrac{4}{9}\cdot\dfrac{35}{118}+\dfrac{5}{9}\cdot\dfrac{35}{118}-\dfrac{35}{118}\\ =\dfrac{38}{118}\left(\dfrac{4}{9}+\dfrac{5}{9}-1\right)\\ =\dfrac{38}{118}\cdot0=0\)
\(\dfrac{4}{9}\cdot\dfrac{35}{118}+\dfrac{5}{9}\cdot\dfrac{35}{118}-\dfrac{35}{118}\)
\(=\dfrac{35}{118}\left(\dfrac{4}{9}+\dfrac{5}{9}-1\right)\)
=0
`@` `\text {Ans}`
`\downarrow`
`317 - (118 - x) = 217`
`=> 118 - x = 317 - 217`
`=> 118 - x = 100`
`=> x = 118 - 100`
`=> x = 18`
Vậy, `x = 18.`
317 - ( 118 - x ) = 217
⇒ 118 - x = 317 - 217
⇒ 118 - x = 100
⇒ x = 118 - 100
⇔ x = 18.
Vậy x = 18.
= \(\left(117^3x117^2x117\right)+\left(118x118^2x118^3\right)+\left(3x3\right)\)
= \(117^6+118^6+9\)
Chốt 1 câu duy nhất, DỄ MÀ
118 x 118 = 13924
118 x 188 = 35344
k nha bn thanks @@