3/2 : x/2 = 6 : 0,3
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a) \(\dfrac{3}{4}\times x:\dfrac{1}{2}=\dfrac{4}{5}\)
\(\dfrac{3}{4}\times x=\dfrac{4}{5}\times\dfrac{1}{2}\)
\(\dfrac{3}{4}\times x=\dfrac{2}{5}\)
\(x=\dfrac{2}{5}:\dfrac{3}{4}\)
\(x=\dfrac{8}{15}\)
b) \(\left(14-x:6\right)\times7=84\)
\(14-x:6=84:7\)
\(14-x:6=12\)
\(x:6=14-12\)
\(x:6=2\)
\(x=6\times2=12\)
c) \(x\times1,5:2,4=0,3\)
\(x\times1,5=0,3\times2,4\)
\(x\times1,5=0,72\)
\(x=0,72:1,5\)
\(x=0,48\)
d) Thiếu x
\(a.\frac{x}{-15}=\frac{60}{2}\)
\(\Rightarrow2x=60\times\left(-15\right)\)
\(\Rightarrow2x=-900\)
\(\Rightarrow x=-900\div2\)
\(\Rightarrow x=-450\)
a: =6-6=0
b: \(=\dfrac{-5}{4}:\dfrac{2-7}{8}+\dfrac{3}{2}\cdot\dfrac{2-5}{6}\)
\(=\dfrac{-5}{4}\cdot\dfrac{8}{-5}+\dfrac{3}{2}\cdot\dfrac{-3}{6}\)
\(=2+\dfrac{-9}{12}=2-\dfrac{3}{4}=\dfrac{5}{4}\)
c: \(=2,5\cdot\left(-0,65\right)+1,5\left(-0,3-0,35\right)=-0,65\cdot4=-2,6\)
\(1\frac{2}{3}:\frac{x}{4}=6:0,3\)
\(\frac{5}{3}:\frac{x}{4}=20\)
\(\Rightarrow\frac{x}{4}=\frac{5}{3}:20\)
\(\Rightarrow\frac{x}{4}=\frac{1}{12}\Rightarrow x=\frac{4}{12}=\frac{1}{3}\)
3) \(\frac{x-3}{x-2}=\frac{4}{7}\)
\(\Rightarrow\left(x-3\right).7=\left(x-2\right).4\)
\(\Rightarrow7x-21=4x-8\)
\(\Rightarrow7x-4x=\left(-8\right)+21\)
\(\Rightarrow3x=13\)
\(\Rightarrow x=13:3\)
\(\Rightarrow x=\frac{13}{3}\)
Vậy \(x=\frac{13}{3}.\)
4) \(\left|x\right|+3,5=0\)
\(\Rightarrow\left|x\right|=0-3,5\)
\(\Rightarrow\left|x\right|=-3,5\)
Vì \(\left|x\right|\ge0\) \(\forall x.\)
\(\Rightarrow\left|x\right|>-3,5\)
\(\Rightarrow\left|x\right|\ne-3,5\)
Vậy \(x\in\varnothing.\)
5) \(\left|x+\frac{1}{3}\right|-4=1\)
\(\Rightarrow\left|x+\frac{1}{3}\right|=1+4\)
\(\Rightarrow\left|x+\frac{1}{3}\right|=5.\)
\(\Rightarrow\left[{}\begin{matrix}x+\frac{1}{3}=5\\x+\frac{1}{3}=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5-\frac{1}{3}\\x=\left(-5\right)-\frac{1}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{14}{3}\\x=-\frac{16}{3}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{14}{3};-\frac{16}{3}\right\}.\)
Chúc bạn học tốt!
a.=> \(\frac{\left(\frac{1}{3}\right).x}{\frac{2}{3}}=\frac{\frac{7}{4}}{\frac{2}{5}}\)
=> \(\frac{1}{3}.x=\frac{7}{4}.\frac{2}{3}:\frac{2}{5}\)
=>\(\frac{1}{3}.x=\frac{35}{12}\)
=> x\(=\frac{35}{12}:\frac{1}{3}\)
Vậy x=\(\frac{35}{4}\).
b. => \(\frac{4,5}{0,3}=\frac{2,25}{0,1.x}\)
=>\(0,1.x=\frac{2,25.0,3}{4,5}\)
=>\(0,1.x=0,15\)
=>\(x=0,15:0,1\)
Vậy x=1,5
c. =>\(\frac{8}{\frac{1}{4}.x}=\frac{2}{0,02}\)
=>\(\frac{1}{4}.x=\frac{8.0,02}{2}\)
=>\(\frac{1}{4}.x=0,08\)
=>\(x=0,08:\frac{1}{4}\)
Vậy x=0,32.
d. =>\(\frac{3}{\frac{9}{4}}=\frac{\frac{3}{4}}{6.x}\)
=>\(3.6x=\frac{9}{4}.\frac{3}{4}\)
=>\(18x=\frac{27}{16}\)
=>\(x=\frac{27}{16}:18\)
Vậy x=\(\frac{3}{32}\)
3./2:x/ .2 = 20
3./2:x/ = 20:2 = 10
/2:x/ = \(\frac{10}{3}\)
\(\Leftrightarrow\orbr{\begin{cases}2:x=\frac{10}{3}\\2:x=\frac{-10}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{5}\\x=\frac{-3}{5}\end{cases}}\)
Vậy....................................................