Tren duong thang xy lay hai diem A va B.Goi M la trung diem cua doan thang AB,biet AM=12cm.Tinh MA,MB
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a) Vì trên đường thẳng xy, lần lượt lấy các điểm A, B, C theo thứ tự đó sao cho AB = 6cm; AC = 8cm ta có:
AB + AC = AC
6 + BC = 8
=> BC = 2 (2cm)
b) Vì M là trung điểm của AB nên
AM = MB AB 6=3 cm
- Trên tia Ay có AB < AC, M là trung điểm của AB nên điểm B nằm giữa M và C ta có: MB + BC = MC
=> 3 + 2 = MC
=> MC = 5 cm
Vậy AB > MC ( 6 > 5)
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đâu phải Huy ko pít làm, Huy nói chtt là vào câu hỏi tương tự để trả lời thôi mà bạn! ^^
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Bạn tự vẽ hình và viết gt kl nha!
a) Ta có: AE = AB + BE
AC = AD + DC
mà AB = AD
BE = DC
suy ra AE = AC
Xét 2 tam giác ABC và tam giác ADE có:
AE = AC (cmt)
AB = AD (gt)
 là góc chung
suy ra tam giác ABC = tam giác ADE (c-g-c)
b) Bạn tự vẽ hình nha!
Xét 2 tam giác vuông MAI và tam giác MBI có:
AM = MB (gt)
MI là cạnh chung
suy ra tam gics MAI = tam gics MBI (2 cạnh góc vuông)
suy ra MA =MB (2 cạnh tương ứng)
Vậy MA =MB
bài này thì dễ thui
nhưng mk ko thick làm toán hình cho lắm
mà bây giờ mk chán quá à
chả có ai nói chuyện cùng
ai kb với mk ko???
MA=12cm MB=12cm vì M là trung điểm của A và B