(1 2/3-2.x).75%-2=13/16
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\(3^x-15=12\\ \Rightarrow3^x=27\\ \Rightarrow x=3\)
\(5^{x-1}-12=13\\ \Rightarrow5^{x-1}=25\\ \Rightarrow x=3\)
\(3^{x-2}.9=81\\ \Rightarrow3^{x-2}=9\\ \Rightarrow x=4\)
\(3^{x+1}:9=3\\ \Rightarrow3^{x+1}=27\\ \Rightarrow x=2\)
\(2.x^3=16\\ \Rightarrow x^3=8\\ \Rightarrow x=2\)
\(75:x^2=3\\ \Rightarrow x^2=25\\ \Rightarrow x=\pm2\)
Câu cuối cộng trừ 5
a,x+9=20-(12-75)-(-8)
x+9=20-(-63) + 8
x+9 = 20 + 63 + 8
x+9 = 91
x = 91 - 9
x = 82.
Vậy x = 82.
b,2.|x-3|=16-(-3)-(-13)-2
2.|x-3|=16 + 3 + 13 - 2
2.|x-3|= 30
|x-3| = 30:2
|x-3| = 15
\(\Rightarrow\orbr{\begin{cases}x-3=15\\x-3=-15\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=18\\x=-12\end{cases}}\)
Vậy x \(\in\){ 18 ; -12 }
# HOK TỐT #
a, x+9=20-(12-75)-(-8)
x+9=91
x =91-9
x =82
b,2.|x-3|=16-(-3)-(-13)-2
2.|x-3| =30
|x-3|=30:2
|x-3|=15
--> x-3=15 hoặc x-3= -15
x=15+3 x= -15+3
x=18 x= -12
Vậy x thuộc {18;-12}
`a)1 4/23 + ( 5/21-4/23)+16/21-1/2`
`=27/23+5/21-4/23+16/21-1/2`
`=(27/23-4/23)+(5/21+16/21)-1/2`
`=23/23+21/21-1/2`
`=1+1-1/2`
`=2-1/2`
`=4/2-1/2`
`=3/2`
___
`b)75%-(5/2+5/3)+(-1/2)^3`
`=3/4-5/2+5/3+(-1/8)`
`=(3/4-5/2-1/8)+5/3`
`=(6/8-20/8-1/8)+5/3`
`=-15/8+5/3`
`=-45/24+40/24`
`=-5/24`
___
`c)-3/4(-55/9).8/11`
`=-3/4.(-40/9)`
`=-10/3`
__
`d)-3/8 . 6/13 + 7/13 . (-3/8) + 1 3/8`
`= -3/8 . (6/13 + 7/13) + 11/8`
`= -3/8 . 13/13 + 11/8`
`= -3/8 .1 + 11/8`
`= -3/8 + 11/8`
`= 8/8`
`=1`
1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
a.\(\dfrac{27}{8}\)
b.\(\dfrac{37}{40}\)
c.\(\dfrac{5}{2}\)
d.\(\dfrac{7}{3}\)
e.5
g.\(\dfrac{53}{16}\)
Bài 1 :
a) \(\dfrac{3}{2}+\dfrac{5}{4}+\dfrac{5}{8}=\dfrac{12}{8}+\dfrac{10}{8}+\dfrac{5}{8}=\dfrac{12+10+5}{8}=\dfrac{27}{8}\)
b) \(\dfrac{4}{5}-\dfrac{3}{8}+\dfrac{2}{4}=\dfrac{32}{40}-\dfrac{15}{40}+\dfrac{20}{40}=\dfrac{32-15+20}{40}=\dfrac{37}{40}\)
c) \(3+\dfrac{6}{8}-\dfrac{5}{4}=\dfrac{3}{1}+\dfrac{6}{8}-\dfrac{5}{4}=\dfrac{24}{8}+\dfrac{6}{8}-\dfrac{10}{8}=\dfrac{20}{8}=\dfrac{5}{2}\)
d) \(\dfrac{5}{6}-\dfrac{1}{2}+2=\dfrac{5}{6}-\dfrac{1}{2}+\dfrac{2}{1}=\dfrac{5}{6}-\dfrac{3}{6}+\dfrac{12}{6}=\dfrac{14}{6}=\dfrac{7}{3}\)
e) \(\dfrac{3}{5}+\dfrac{6}{11}+\dfrac{7}{13}+\dfrac{2}{5}+\dfrac{16}{11}+\dfrac{19}{13}=\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{6}{11}+\dfrac{16}{11}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)=1+2+2=5\)
g) \(\dfrac{75}{100}+\dfrac{18}{21}+\dfrac{29}{32}+\dfrac{1}{4}+\dfrac{3}{21}+\dfrac{13}{32}=\dfrac{3}{4}+\dfrac{6}{7}+\dfrac{29}{32}+\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{6}{7}+\dfrac{1}{7}\right)+\left(\dfrac{29}{32}+\dfrac{13}{32}\right)=1+1+\dfrac{21}{16}=2+\dfrac{21}{16}=\dfrac{53}{16}\)
3:
a: -5x-16=-46
=>-5x=-46+16=-30
=>5x=30
=>\(x=\dfrac{30}{5}=6\)
b: -80-(-16-x)=20
=>\(-x-16=-80-20=-100\)
=>x+16=100
=>x=100-16=84
2:
a: \(\left(45-3456\right)+3456\)
\(=45+3456-3456\)
=45
b: \(\left(77+22-75\right)-\left(-25-78-13\right)\)
\(=77+13+22+78-75+25\)
\(=90+100-50\)
=140
c: \(-25\cdot63-25\cdot37\)
\(=-25\left(63+37\right)\)
\(=-25\cdot100=-2500\)
(1 2/3-2.x).75%-2=13/16
(5/3-2x). 75/100=13/16+2=45/16
(5/3-2x)=\(\frac{45}{16}\).\(\frac{100}{75}\)=\(\frac{15}{4}\)
2x=\(\frac{5}{3}\)-\(\frac{15}{4}\)=-\(\frac{25}{12}\)
x=-\(\frac{25}{24}\)