Trung bình cộng của hai số là 315 Số thứ nhất hơn số thứ hai là 126 Tìm hai số đó
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Tổng 3 số là:
315x3=945
Số thứ nhất hơn tổng hai số kia là:
75+(75+45)=195 đơn vị
Số thứ nhất là:
(945+195):2=570
Sô thứ hai là:
570-75=495
Đ/s:..........
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Gọi số thứ nhất, hai , ba theo thứ tự đề bài là a, b và c.
Theo đề bài, ta có (a+b+c):3 = 126 ; a - b = 15 suy ra a = b+15 ; b - c =9 suy ra c = b - 9
Do đó \(\frac{a+b+c}{3}=126\Rightarrow b+15+b+b-9=378\Rightarrow3b=372\Rightarrow b=124\Rightarrow c=124-9=115\)
Vậy số thứ ba là 115
Tổng 3 số là \(\dfrac{7}{8}\times3=\dfrac{21}{8}\)
Số thứ ba là \(\dfrac{21}{8}:\left(2+1\right)\times1=\dfrac{7}{8}\)
Số thứ nhất là \(\left[\left(\dfrac{21}{8}-\dfrac{7}{8}\right)+\dfrac{1}{5}\right]:2=\dfrac{39}{40}\)
Số thứ hai là \(\dfrac{39}{40}-\dfrac{1}{5}=\dfrac{31}{40}\)
TBC của ST1 và ST2 bằng ST3 mà TBC của 3 số = 5/8 => ST3 = 5/8.
Tổng của ST1 và ST2 là: 5/8 x 2 = 5/4
Số thứ nhất là: (5/4 + 1/4) : 2 = 3/4
Số thứ 2 là: 3/4 - 1/4 = 1/2
Đáp số: 3/4, 1/2 và 5/8
Số thứ 3= trung bình cộng của số thứ 1 và số thứ 2 nên số thứ thứ 3= trung bình cộng của 3 số là 5/8
Tổng của số thứ 1 và số thứ 2 là:5/8x2=10/8
Số thứ 2 là:[5/4-1/4]:2=1/2
Số thứ 1 là:1/2+1/4=3/4
Số thứ ba là:5/8
Tổng của hai số đó là:
\(315\times2=630\)
Số thứ nhất là:
\(\left(630+126\right)\div2=378\)
Số thứ hai là:
\(378-126=252\)