tinh
B=3+3x6^2+6^2/13
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a) \(\dfrac{\left(0,6\right)^5}{\left(0,2\right)^6}=\dfrac{\left(0,2.3\right)^5}{\left(0,2\right)^5.\left(0,2\right)}=\dfrac{\left(0,2\right)^5.3^5}{\left(0,2\right)^5.\left(0,2\right)}=\dfrac{3^5}{0,2}=\dfrac{243}{0,2}=1215\)
c) \(2:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^2=2:\left(\dfrac{3}{6}-\dfrac{4}{6}\right)^2=2:\left(-\dfrac{1}{6}\right)^2=2:\dfrac{1}{36}=72\)
\(\frac{2}{1.3}+\frac{3}{3.6}+\frac{4}{6.10}+\frac{5}{10.15}+\frac{6}{15.21}\)
= \(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{21}\)
= \(1-\frac{1}{21}\)
= \(\frac{20}{21}\)
Ủng hộ mk nha !!! ^_^
\(b,\frac{10^3+5x10^2+5^3}{6^3+3x6^2+3^3}\)
\(=\frac{5\left(200+10^2+5^2\right)}{3\left(72+6^2+3^2\right)}\)
\(=\frac{5\left(200+100+25\right)}{3\left(72+36+9\right)}\)
\(=\frac{5.325}{3.117}\)
\(=\frac{125}{27}\)