Tìm x
a. X x 1,5 = 3
b. X : 1,5 = 3
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a)\(\left|x-3,5\right|=0,25\)
\(\Leftrightarrow\orbr{\begin{cases}x-3,5=0,25\\x-3,5=-0,25\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3,75\\x=3,25\end{cases}}}\)
b)\(\left|1,5-x\right|=1,75\)
\(\Leftrightarrow\orbr{\begin{cases}1,5-x=1,75\\1,5-x=-1,75\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-0,25\\x=3,25\end{cases}}}\)
c)\(\left|x-1,5\right|=1,5\)
\(\Leftrightarrow\orbr{\begin{cases}x-1,5=1,5\\x-1,5=-1,5\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\x=0\end{cases}}}\)
\(a,\left(x-\dfrac{1}{3}\right)\left(x+\dfrac{2}{3}\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-\dfrac{2}{3}\end{matrix}\right.\\ b,\left(\dfrac{3}{4}x-\dfrac{9}{16}\right)\left(1,5+\dfrac{-3}{x}\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}x=\dfrac{9}{16}\\-\dfrac{3}{x}=-1,5=-\dfrac{3}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=2\end{matrix}\right.\)
a: \(\left(x-\dfrac{1}{3}\right)\left(x+\dfrac{2}{3}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-\dfrac{2}{3}\end{matrix}\right.\)
b: \(\left(\dfrac{3}{4}x-\dfrac{9}{16}\right)\left(\dfrac{1}{5}+\left(-3\right):x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}x=\dfrac{9}{16}\\\left(-3\right):x=-\dfrac{1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{16}:\dfrac{3}{4}=\dfrac{9}{16}\cdot\dfrac{4}{3}=\dfrac{3}{4}\\x=\left(-3\right):\dfrac{-1}{5}=15\end{matrix}\right.\)
Làm:
\(1,5\cdot x-\frac{7}{3}x=1,5-\frac{2}{3}\)
\(\left(1,5-\frac{7}{3}\right)x=\frac{5}{6}\)
\(\Leftrightarrow\) \(-\frac{5}{6}x=\frac{5}{6}\)
\(\Leftrightarrow\) \(x=-1\)
~ học tốt ~
1,5 . x - 7/3 . x = 1,5 - 2/3
=> 1,5 . x - 7/3 . x = 5/6
=>1,5 . x = 5/6 - 7/3
=> 1,5 . x = - 3/2
=> x = - 3/2 : 1,5
=> x = -1
Vay x = - 1
a) x . 1,5 = 3
x = 3 : 1,5
x = 2
b) x : 1,5 = 3
x = 3 . 1,5
x = 4,5
Dấu "." là dấu "x"