80-7=?
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B = \(\frac{7}{2.4}+\frac{7}{4.6}+\frac{7}{6.8}+.....+\frac{7}{100.102}\)
ta có \(\frac{7}{2.4}=\frac{1}{2}\left(\frac{7}{2}-\frac{7}{4}\right);\frac{7}{4.6}=\frac{1}{2}\left(\frac{7}{4}-\frac{7}{8}\right);......;\frac{7}{100.102}=\frac{1}{2}\left(\frac{7}{100}-\frac{7}{102}\right)\)
⇒ B = \(\frac{1}{2}\left(\frac{7}{2}-\frac{7}{4}+\frac{7}{4}-\frac{7}{8}+....+\frac{7}{100}-\frac{7}{102}\right)\)
⇔ B = \(\frac{1}{2}\left(\frac{7}{2}-\frac{7}{102}\right)\)
⇔ B = \(\frac{1}{2}.\frac{175}{51}\)
⇔ B = \(\frac{175}{102}\)
\(80-7\left(x-7\right)=95-3^2.6\)
\(\Rightarrow80-7\left(x-7\right)=95-54\)
\(\Rightarrow80-7\left(x-7\right)=41\)
\(\Rightarrow7\left(x-7\right)=80-41\)
\(\Rightarrow7\left(x-7\right)=39\)
\(\Rightarrow x-7=\dfrac{39}{7}\)
\(\Rightarrow x=\dfrac{39}{7}+7\)
\(\Rightarrow x=\dfrac{39}{7}+\dfrac{49}{7}\)
\(\Rightarrow x=\dfrac{88}{7}\)
\(80-7\left(x-7\right)=95-3^2.6\)
\(80-7\left(x-7\right)=95-9.6\)
\(80-7\left(x-7\right)=95-54\)
\(80-7\left(x-7\right)=41\)
\(7\left(x-7\right)=80-41\)
\(7\left(x-7\right)=49\)
\(x-7=49:7\)
\(x-7=7\)
\(x=7+7\)
\(\Rightarrow x=14\)
253 = 200 + 50 + 3
675 = 600 + 70 + 5
810 = 800 + 10
508 = 500 + 8
300 + 20 + 7 = 327
400 + 80 + 2 = 482
300 + 5 = 305
700 + 80 = 780
80-7=73
Hieu la:
80 - 7 = 73
Dap so:73