Tinh hop li:
192:16
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\(-1+6+\left(-11\right)+16+....+996+\left(-1001\right)\)
\(=5+5+....+5+5\)
\(=5.10\)
\(=50\)
-1+6+(-11)+16+.....+996+(-1001)
=[-1+6]+[-11+16]+....+[-991+996]+(-1001)
=5 + 5 +...+ 5 + (-1001)
có 100 số 5
=5 x100+(-1001)
=500+(-1001)
=-501
k cho minh nha
chúc bạn học giỏi
= (32-12)+(34-14)+(36-16)+(38-18)-10
= 20+20+20+20-10
= 80-10
= 70
32+34+36+38-10-12-14-16-18
=(32-12)+(34-14)+(36-16)+(38-18)-10
=20+20+20+20-10
=20 x 4-10
=80-10
=70
= (11+19) + (12+18) + (13+17) + (14+16) + (10+15)
= 30 + 30 + 30 + 30 + 25 = 145
A = 10 + (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) + 15
= 10 + 30 + 30 + 30 + 30 + 15 = 145
a) (273 - 51) - [73 - (-149)]
= 273 - 51 - 73 - 149
= (273 - 73) - (51 + 149)
= 200 - 200
= 0
b) 130 - [13 . 3 - (19-16)2
= 130 - (39 - 32)
= 130 - (39 - 9)
= 130 - 30
= 100
a) \(\left(273-51\right)-\left[73-\left(-149\right)\right]\)
\(=273-51-73-149\)
\(=\left(273-73\right)-\left(51+149\right)\)
\(=200-200\)
\(=0\)
b) \(130-\left[13.3-\left(19-16\right)^2\right]\)
\(=130-\left(39-3^2\right)\)
\(=130-\left(39-9\right)\)
\(=130-30\)
\(=100\)
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)
=> \(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
=> \(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\right)\)
=> \(A=1-\frac{1}{32}=\frac{31}{32}\)
A.\(\dfrac{4}{20}\)+\(\dfrac{16}{42}\)+\(\dfrac{6}{15}\)+\(\dfrac{-3}{5}\)+\(\dfrac{2}{21}\)+\(\dfrac{-10}{21}\)+\(\dfrac{3}{20}\)
=\(\dfrac{1}{5}\)+\(\dfrac{8}{21}\)+\(\dfrac{6}{15}\)+\(\dfrac{-3}{5}\)+\(\dfrac{2}{21}\)+\(\dfrac{-10}{21}\)+\(\dfrac{3}{20}\)
=\((\dfrac{1}{5}\)+\(\dfrac{6}{15}\)+\(\dfrac{-3}{5}\)\()\)+\((\dfrac{8}{21}\)+\(\dfrac{2}{21}\)+\(\dfrac{-10}{21}\)\()\)+\(\dfrac{3}{20}\)
=\((\)\(\dfrac{1}{5}\)+\(\dfrac{2}{5}\)+\(\dfrac{-3}{5}\)\()\)+ 0 +\(\dfrac{3}{20}\)
= 0 + 0 +\(\dfrac{3}{20}\)
=\(\dfrac{3}{20}\)
B.\(\dfrac{42}{46}\)+\(\dfrac{250}{286}\)+\(\dfrac{-2121}{2323}\)+\(\dfrac{-125125}{143143}\)
=\(\dfrac{21}{23}\)+\(\dfrac{125}{143}\)+\(\dfrac{-21}{23}\)+\(\dfrac{-125}{134}\)
=\((\dfrac{21}{23}+\dfrac{-21}{23})+(\dfrac{125}{143}+\dfrac{-125}{134})\)
= 0 + 0
= 0
Chúc bạn Tran Mai học tốt nha
192:16=12:1(chia cả 2 số cho 16 nhưng thưong vẫn ko đổi)=12
k nhé