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a) Ta có: \(3x^2+5y-3xy-5x\)

\(=3x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(3x-5\right)\)

b) Ta có: \(3y^2-3z^2+3x^2+6xy\)

\(=3\left(y^2-z^2+x^2+2xy\right)\)

\(=3\left[\left(x+y\right)^2-z^2\right]\)

\(=3\left(x+y-z\right)\left(x+y+z\right)\)

c) Ta có: \(x^2-25-2xy+y^2\)

\(=\left(x-y\right)^2-5^2\)

\(=\left(x-y-5\right)\left(x-y+5\right)\)

d) Ta có: \(5x^2-10xy+5y^2-20z^2\)

\(=5\left(x^2-2xy+y^2-4z^2\right)\)

\(=5\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)

\(=5\left(x-y-2z\right)\left(x-y+2z\right)\)

e) Ta có: \(x^2-5x+5y-y^2\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y-5\right)\)

f) Ta có: \(3x^2-6xy+3y^2-12z^2\)

\(=3\left(x^2-2xy+y^2-4z^2\right)\)

\(=3\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)

\(=3\left(x-y-2z\right)\left(x-y+2z\right)\)

14 tháng 12 2022

`a)7x^3y^2+14x^2y^3+7xy^4`

`=7xy^2(x^2+2xy+y^2)`

`=7xy^2(x+y)^2`

______________________________________________

`b)x^2-xy+5x-5y`

`=x(x-y)+5(x-y)`

`=(x-y)(x+5)`

______________________________________________

`c)3x^2-6xy-12+3y^2`

`=3(x^2-2xy-4+y^2)`

`=3[(x-y)^2-4]`

`=3(x-y-2)(x-y+2)`

a)7x3y2+14x2y3+7xy4

=7xy2(x2+2xy+y2)

=7xy2(x+y)2

b)x2-xy + 5x - 5y

=x(x-y) + 5(x-y)

=(x-y) (x+5)

 

19 tháng 6 2015

b)x2+2xy+y2-16=(x+y)2-42=(x+y+4)(x+y-4)

c)3x2+5x-3xy-5y=x(3x+5)-y(3x+5)=(3x+5)(x-y)

d)4x2-6x3y-2x2+8x=2x(2x-3x2y-x+4)

e)x2-4-2xy+y2=(x2-2xy+y2)-4=(x-y)2-22=(x-y-2)(x-y+2)

k)x2-y2-z2-2yz=x2-(y+z)2=(x-y-z)(x+y+z)

m)6xy+5x-5y-3x2-3y2=3(x2-2xy+y2)+5(x-y)=3(x-y)2+5(x-y)=(x-y)(3x-3y+5)


 

27 tháng 6 2016

b. (x^2+2xy+y^2)-16 =(x+y)^2-16=(x+y+4)(x+y-4)

28 tháng 8 2019

6xy + 5x − 5y − 3x2 − 3y2

=5(x−y)−(3x2−6xy+3y2)

=5(x−y)−3(x−y)2

=5(x−y)−(3x−3y)(x−y)

=(5−3x+3y)(x−y)

30 tháng 8 2019

thank nha

6 tháng 4 2020

\(a.\left(8x^4-4x^3+x^2\right):2x^2=4x^2-2x+\frac{1}{2}\)

\(b.\left(2x^4-x^3+3x^2\right):\left(-\frac{1}{3x^2}\right)=-6x^6+3x^5-9x^4\)

\(c.\left(-18x^3y^5+12x^2y^2-6xy^3\right):6xy=-3x^2y^4+2xy-y^2\)

\(d.\left(\frac{3}{4x^3y^6}+\frac{6}{5x^4y^5}-\frac{9}{10x^5y}\right):-\frac{3}{5x^3y}=-\frac{5}{4y^5}-\frac{2}{xy^4}-\frac{3}{2x^2}\)

6 tháng 4 2020

Thank you

24 tháng 8 2023

\(x^2-y^2+5x-5y\)

\(=\left(x-y\right)\left(x+y\right)+5\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y+5\right)\)

\(---\)

\(x^2-16y^2+4x+4\)

\(=\left(x^2+4x+4\right)-16y^2\)

\(=\left(x+2\right)^2-\left(4y\right)^2\)

\(=\left(x+2-4y\right)\left(x+2+4y\right)\)

\(=\left(x-4y+2\right)\left(x+4y+2\right)\)

\(---\)

\(3x^2+6xy+3y^2-12\)

\(=3\left(x^2+2xy+y^2-4\right)\)

\(=3\left[\left(x+y\right)^2-2^2\right]\)

\(=3\left(x+y-2\right)\left(x+y+2\right)\)

\(---\)

\(4x^3+4x^2+x\)

\(=x\left(4x^2+4x+1\right)\)

\(=x\left(2x+1\right)^2\)

20 tháng 10 2021

2)3x2-6xy+3y2=3(x2-2xy+y2)=3(x-y)2

3)3(x-y)-5y(y-x)=3(x-y)+5y(x-y)=(x-y)(3+5y)

5)(x+y)3-(x-y)3=[(x+y)-(x-y)][(x+y)2+(x+y)(x-y)+(x-y)2]=(x+y-x+y)(x2+2xy+y2+x2-y2+x2-2xy+y2)=2y(3x2+y2)

6)3x2-5x+2=3x2-2x-3x+2=(3x2-3x)-(2x-2)=3x(x-1)-2(x-1)=(x-1)(3x-2)

19 tháng 6 2015

a) x^2+2xy+y^2-16

=(x+y)2-16

=(x+y-4)(x+y+4)

b) 3x^2+5x-3xy-5y

=(3x2-3xy)+(5x-5y)

=3x(x-y)+5(x-y)

=(x-y)(3x+5)

c) 4x^2-6x^3y-2x^2+8x

ko bik hoặc sai đề

d) x^2-4-2xy+y^2

=(x-y)2-4

=(x-y+2)(x-y-2)

e) x^3-4x^2-12x+27

=sai đề

g) 3x^2-18x+27

=3(x2-6x+9)

=3(x-3)2

h) x^2-y^2-z^2-2yz

=x2-(y2+z2+2yx)

=x2-(y+z)2

=(x-y-z)(x+y+z)

k) 4x^2(x-6)+9y^2(6-x)

=4x2(x-6)-9y2(x-6)

=(x-6)(4x2-9y2)

=(x-6)(2x-3y)(2x+3y)

l)6xy+5x-5y-3x^2-3y^2

=(5x-5y)+(-3x2+6xy-3y2)

=5(x-y)-3(x2-2xy+y2)

=5(x-y)-3(x-y)2

=(x-y)(5-3(x-y))

=(x-y)(5-3x+3y)