Tìm x
x:4=1053 81:x=45:5
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\(4^{x-5}=16\)
\(4^{x-5}=4^2\)
\(x-5=2\)
\(x=2+5\)
\(x=7\)
\(45-2^{x-1}=29\)
\(2^{x-1}=16\)
\(2^{x-1}=2^4\)
\(x-1=4\)
\(x=5\)
\(\left(2+x\right)^2=144\)
\(\left(2+x\right)^2=12^2\)
\(2+x=12\)
\(x=12-2\)
\(x=10\)
\(\left(x-5\right)^2=81\)
\(\left(x-5\right)^2=9^2\)
\(x-5=9\)
\(x=14\)
\(\left(13-x\right)^4=81\)
\(\left(13-x\right)^4=3^4\)
\(13-x=3\)
\(x=13-3\)
\(x=10\)
\(...4^{x-5}=4^2\Rightarrow x-5=2\Rightarrow x=7\)
\(...2^{x-1}=45-29=16\Rightarrow2^{x-1}=2^4\Rightarrow x-1=4\Rightarrow x=5\)
\(...\Rightarrow\left(2+x\right)^2=12^2\Rightarrow\left[{}\begin{matrix}2+x=12\\2+x=-12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=10\\x=-14\end{matrix}\right.\)
\(...\Rightarrow\left(x-5\right)^2=9^2\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
\(...\Rightarrow\left(13-x\right)^4=3^4\Rightarrow\left[{}\begin{matrix}13-x=3\\13-x=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=10\\x=16\end{matrix}\right.\)
a) \(3^{x-1}+3x+3^{x+1}=1053\)
\(=3^x:3+3^x+3^x.3=1053\)
\(=3^x.\dfrac{1}{3}+1+3=1053\)
\(=3^x.\dfrac{13}{5}=1053\)
\(=3^x=243\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
a/
x= 918 : 9 = 102
b/
13590 : 45 = 302
c/
x = 1834 . 15 = 27510
d/
6.x = 240
=> x= 240 : 6 = 40
e/
5.x = 450
=> x= 450 : 5 = 90
f/
21-x = 9
=> x= 21-9 = 12
a. 3x+3x+1+3x+2=1053
=> 3x.(1+3+32)=1053
=> 3x.(1+3+9)=1053
=> 3x.13=1053
=> 3x=1053:13
=> 3x=81
=> 3x=34
=> x=4
b. 5x.519=520.511
=> 519+x=520+11
=> 19+x=20+11
=> 19+x=31
=> x=31-19
=> x=12
\(3^x+3^{x+1}+3^{x+2}=1053\)
\(3^x\left(1+3+3^2\right)=1053\)
\(3^x\cdot13=1053\)
\(3^x=1053:13=81\)
\(3^x=3^4\)
=> x = 4
3^x+3^(x+1)+3^(x+2)=1053 <=> 3^x+3^1*3^x+3^2*3^x=1053
<=> (1+3^1+3^2)*3^x=1053
<=>3^x= 1053/ (1+3+9)
<=> 3^x=81
=> x=4
x : 4 = 1053 81 : x = 45 : 5
x = 1053 x 4 81 : x = 9
x = 4212 x = 81 : 9
x = 9
1,x:4=1053 2,81:x=45:5
x=1053nhân 4 81:x=5 x=4212 x=81chia9