1+2+3+4+5+6+7+.....+1267
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\(a,\left(1267-196\right)-\left(1267-396\right)\)
\(=1267-196-1267+396\)
\(=\left(1267-1267\right)-\left(196-396\right)\)
\(=0-\left(-200\right)\)
\(=0+200\)
\(=200\)
a, ( 1267 - 196 ) - ( 1267 - 396 )
= 1267 - 196 - 1267 - 396
= ( 1267 - 1267 ) - ( 196 - 396 )
=0 - ( - 200 )
= 0+ 200
= 200
5: \(=3-\dfrac{1}{4}+\dfrac{2}{3}-5+\dfrac{1}{3}+\dfrac{6}{5}-6+\dfrac{7}{4}-\dfrac{3}{2}\)
\(=3-5-6+\dfrac{-1}{4}+\dfrac{7}{4}+\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{6}{5}-\dfrac{3}{2}\)
\(=-8+\dfrac{3}{2}+1+\dfrac{-3}{10}\)
\(=-7+\dfrac{15-3}{10}=-7+\dfrac{6}{5}=-\dfrac{29}{5}\)
6: \(=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}\)
\(=6-5-3-\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{7}{3}+\dfrac{1}{2}+\dfrac{3}{2}-\dfrac{5}{2}\)
\(=-2-\dfrac{1}{2}=-\dfrac{5}{2}\)
7: \(=\dfrac{5}{3}-\dfrac{3}{7}+9-2-\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{8}{7}-\dfrac{4}{3}-10\)
\(=9-2-10+\dfrac{5}{3}+\dfrac{2}{3}-\dfrac{4}{3}+\dfrac{-3}{7}-\dfrac{5}{7}+\dfrac{8}{7}\)
=-3+1
=-2
8: \(=8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)
\(=8+6-3+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}-1-\dfrac{2}{4}\)
\(=11+2-1-\dfrac{1}{2}\)
=11+1/2
=11,5
Lời giải chi tiết:
3 + 4 > 6 | 6 + 1 > 6 | 5 + 1 = 6 |
3 + 4 = 7 | 5 + 2 > 6 | 7 – 5 > 3 |
7 – 4 < 4 | 7 – 2 = 5 | 7 – 6 = 1 |
6 + 1 = 7 5 + 2 = 7 4 + 3 = 7
1 + 6 = 7 2 + 5 = 7 3 + 4 = 7
7 - 6 = 1 7 - 5 = 2 7 - 4 = 3
7 - 1 = 6 7 - 2 = 5 7 - 3 = 4
Lời giải chi tiết:
4 + 3 = 7 | 5 + 2 = 7 | 6 + 1 = 7 |
3 + 4 = 7 | 2 + 5 = 7 | 1 + 6 = 7 |
7 – 4 = 3 | 7 – 5 = 2 | 7 – 6 = 1 |
7 – 3 = 4 | 7 – 2 = 5 | 7 – 1 = 6 |
tổng trên = 1267 x ( 1267 + 1 ) : 2 = 803278
1 + 2 + 3 + 4 + 5 + 6 + 7 + .... + 1267 ( 1267 so )
= ( 1 + 1267 ) x 1267 : 2
= 803278