a,a/b+5/6=7/8
b,a/b*2/3=3/4
c,5/8-a/b=5/12
d,5/8+a/b=3/8
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tham khảo
a. 5/8
b. 29/28
c. -1/36
d. -41/24
e. -341/273
f. -17/5
g. -4
`#` `\text{dkhanhqlv}`
`a)-2+(-5/8)`
`=-2-5/8`
`=-16/8-5/8`
`=-21/8`
`b)5+(-3/4)`
`=5-3/4`
`=20/4-3/4`
`=17/4`
`c)4/3+(-6)`
`=4/3-6`
`=4/3-18/3`
`=-14/3`
`d)-8-2/7`
`=-56/7-2/7`
`=-58/7`
`e)-3/5-9`
`=-3/5-45/5`
`=-48/5`
`g)6-(-4/13)`
`=6+4/13`
`=78/13+4/13`
`=82/13`
\(a,\left(-2\right)-\dfrac{5}{8}=-\dfrac{21}{8}\)
\(b,5+\left(-\dfrac{3}{4}\right)=5-\dfrac{3}{4}=\dfrac{20}{4}-\dfrac{3}{4}=\dfrac{17}{4}\)
\(c,\dfrac{4}{3}+\left(-6\right)=\dfrac{4}{3}-6=-\dfrac{14}{3}\)
\(d,\left(-8\right)-\dfrac{2}{7}=-\dfrac{58}{7}\)
\(e,-\dfrac{3}{5}-9=-\dfrac{48}{5}\)
\(g,6-\left(-\dfrac{4}{13}\right)=6+\dfrac{4}{13}=\dfrac{82}{13}\)
a: \(\dfrac{7}{8}+3=\dfrac{3\cdot8+7}{8}=\dfrac{31}{8}\)
b: \(2-\dfrac{5}{4}=\dfrac{2\cdot4-5}{4}=\dfrac{3}{4}\)
\(4\cdot\dfrac{5}{9}=\dfrac{20}{9}\)
d: \(\dfrac{3}{8}:2=\dfrac{3}{16}\)
a.\(\dfrac{2}{3}\times\dfrac{4}{9}+\dfrac{2}{3}\times\dfrac{5}{9}=\dfrac{2}{3}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
b.\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
c.\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
a) 2/3 x 4/9 + 2/3 x 5/9
=2/3 x ( 4/9 + 5/9)
= 2/3 x 1
= 2/3
b, 7/5 x 3/4 - 1/2 x 3/4
= ( 7/5 - 1/2 ) x 3/4
= 9/10 x 3/4
= 21/40
c, ( 5/6 + 5/8 ) x 2/3
= 35/24 x 2/3
= 35/36
a) ta có: \(\frac{a}{4}=\frac{b}{5};\frac{b}{5}=\frac{c}{8}\)
\(\Rightarrow\frac{a}{4}=\frac{b}{5}=\frac{c}{8}=\frac{5a}{20}=\frac{3b}{15}=\frac{3c}{24}\)
ADTCDTSBN
...
bn tự áp dụng rùi tìm a;b;c nha
b) ta có: \(\frac{a+3}{5}=\frac{b-2}{3}=\frac{c-1}{7}=\frac{3a+9}{15}=\frac{5b-10}{15}=\frac{7c-7}{49}\)
ADTCDTSBN
có: \(\frac{3a+9}{15}=\frac{5b-10}{15}=\frac{7c-7}{49}=\frac{3a+9-5b+10+7c-7}{15-15+49}\)
\(=\frac{\left(3a-5b+7c\right)+\left(9+10-7\right)}{49}=\frac{86+12}{49}=\frac{98}{49}=2\)
=>...
c) ta cóL \(\frac{a}{7}=\frac{b}{6}\Rightarrow\frac{a}{35}=\frac{b}{30}\)
\(\frac{b}{5}=\frac{c}{8}\Rightarrow\frac{b}{30}=\frac{c}{48}\)
\(\Rightarrow\frac{a}{35}=\frac{b}{30}=\frac{c}{48}=\frac{2b}{60}\)
ADTCDTSBN
...
các bài còn lại bn dựa vào mak lm nha!
a) Ta có : \(\frac{a}{b}+\frac{5}{6}=\frac{7}{8}\)=> \(\frac{a}{b}=\frac{7}{8}-\frac{5}{6}\)
=> \(\frac{a}{b}=\frac{21}{24}-\frac{20}{24}=\frac{1}{24}\)
Vậy \(\frac{a}{b}=\frac{1}{24}\)
b) \(\frac{a}{b}\times\frac{2}{3}=\frac{3}{4}\)
=> \(\frac{a}{b}=\frac{3}{4}:\frac{2}{3}=\frac{3}{4}\times\frac{3}{2}=\frac{9}{8}\)
Vậy \(\frac{a}{b}=\frac{9}{8}\)
c) \(\frac{5}{8}-\frac{a}{b}=\frac{5}{12}\)
=> \(\frac{a}{b}=\frac{5}{8}-\frac{5}{12}=\frac{15}{24}-\frac{10}{24}=\frac{5}{24}\)
Vậy \(\frac{a}{b}=\frac{5}{24}\)
d) \(\frac{5}{8}+\frac{a}{b}=\frac{13}{8}\)
=> \(\frac{a}{b}=\frac{13}{8}-\frac{5}{8}=\frac{8}{8}=1\)
Vậy : ....
a/
\(\Leftrightarrow A=\dfrac{3}{8}xy^2+B-\dfrac{5}{6}x^2y+\dfrac{3}{4}x^2y-\dfrac{5}{8}xy^2\\ \Leftrightarrow A-B=-\dfrac{1}{12}x^2y-\dfrac{1}{4}xy^2\)
b/
\(\Leftrightarrow A-B=5xy^3-\dfrac{5}{8}yx^3-\dfrac{21}{4}xy^3+\dfrac{3}{7}x^3y\\ \Leftrightarrow A-B=-\dfrac{1}{4}xy^3-\dfrac{11}{56}x^3y\)
a) a/b = 7/8 - 5/6
a/b = 1/24
b) a/b = 3/4 : 2/3
a/b = 9/8
c) a/b = 5/8 - 5/12
a/b= 5/24
d) a/b = 3/8 - 5/8
a/b = -2/8 -1/4