(x- 5/8):5/18=-15/36
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U
21 tháng 7 2018
\(\frac{x}{-4}=\frac{-16}{x}\)
\(\Rightarrow x\cdot x=-16\cdot\left(-4\right)\)
\(\Rightarrow x^2=64\)
\(\Rightarrow x^2=\left(\pm8\right)^2\)
\(\Rightarrow x=\pm8\)
21 tháng 7 2018
a)\(\left(x-\frac{5}{8}\right).\frac{5}{18}=-\frac{15}{36}\)
\(\Rightarrow x-\frac{5}{8}=\frac{-15}{36}.\frac{18}{5}\)
\(\Rightarrow x-\frac{5}{8}=-\frac{3}{2}\)
\(\Rightarrow x=-\frac{12}{8}+\frac{5}{8}=-\frac{7}{8}\)
b)\(\frac{x}{-4}=\frac{-16}{x}\)
\(\Rightarrow x^2=64\)
\(\Rightarrow x=\orbr{\begin{cases}8\\-8\end{cases}}\)
NN
1
G
17 tháng 3 2022
\(a,\left(x-\dfrac{5}{8}\right).\dfrac{5}{8}=-\dfrac{15}{36}\)
\(\left(x-\dfrac{5}{8}\right)=-\dfrac{15}{36}\div\dfrac{5}{8}\)
\(x-\dfrac{5}{8}=-\dfrac{2}{3}\)
\(x=-\dfrac{2}{3}+\dfrac{5}{8}\)
\(x=-\dfrac{1}{24}\)
\(b,\left(x-\dfrac{1}{3}\right)=\dfrac{5}{6}\)
\(\Rightarrow x-\dfrac{1}{3}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}+\dfrac{1}{3}\)
\(x=\dfrac{7}{6}\)
NA
17 tháng 3 2022
\(a,\left(x-\dfrac{5}{8}\right)\cdot\dfrac{8}{18}=-\dfrac{15}{16}\\ x-\dfrac{5}{8}=-\dfrac{15}{36}:\dfrac{8}{18}\\ x-\dfrac{5}{8}=-\dfrac{15}{16}\\ x=-\dfrac{15}{16}+\dfrac{5}{8}\\ x=-\dfrac{15}{16}+\dfrac{10}{16}\\ x=-\dfrac{5}{16}\\ b,x-\dfrac{1}{3}=\dfrac{5}{6}\\ x=\dfrac{5}{6}+\dfrac{1}{3}\\ x=\dfrac{5}{6}+\dfrac{2}{6}\\ x=\dfrac{7}{6}\)
NM
4
CB
7 tháng 7 2016
\(\left(x-\frac{5}{8}\right).\frac{5}{18}=-\frac{15}{36}\)
\(\left(x-\frac{5}{8}\right)=-\frac{15}{36}:\frac{5}{8}\)
\(\left(x-\frac{5}{8}\right)=-\frac{3}{2}\)
\(x=-\frac{3}{2}+\frac{5}{8}\)
\(x=-\frac{7}{8}\)
^...^ ^_^ hihihi
HT
2
30 tháng 7 2016
\(\left(x-\frac{5}{8}\right).\frac{5}{8}=-\frac{15}{36}\)
\(\left(x-\frac{5}{8}\right)=-\frac{15}{36}:\frac{5}{8}\)
\(-\frac{3}{2}\)
x=\(-\frac{3}{2}+\frac{5}{8}=-\frac{7}{8}\)
DL
1
10 tháng 8 2020
Câu 1:
a) Ta có: \(\left(x-\frac{5}{8}\right)\cdot\frac{5}{18}=\frac{15}{36}\)
\(\Leftrightarrow x-\frac{5}{8}=\frac{15}{36}:\frac{5}{8}=\frac{15}{36}\cdot\frac{8}{5}=\frac{120}{180}=\frac{2}{3}\)
\(\Leftrightarrow x=\frac{2}{3}+\frac{5}{8}=\frac{16}{24}+\frac{15}{24}=\frac{41}{24}\)
Vậy: \(x=\frac{41}{24}\)
b) Ta có: \(\left|x-\frac{1}{3}\right|=\frac{5}{6}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\frac{1}{3}=\frac{5}{6}\\x-\frac{1}{3}=-\frac{5}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{5}{6}+\frac{1}{3}=\frac{5}{6}+\frac{2}{6}=\frac{7}{6}\\x=\frac{-5}{6}+\frac{1}{3}=\frac{-5}{6}+\frac{2}{6}=\frac{-3}{6}=\frac{-1}{2}\end{matrix}\right.\)
Vậy: \(x\in\left\{\frac{7}{6};\frac{-1}{2}\right\}\)
14 tháng 6 2023
a: =7/8:(2/9-18+1/36)-5/12
=-7/142-5/12=-397/852
b: =3/7(4/9+5/9:6/12)=2/3
c: =5^8(16/31-47/31)+1/3=-5^8+1/3
d: =7/2(3/8+5/8:4/15)=609/64
\(x-\dfrac{5}{8}=-\dfrac{15}{36}\times\dfrac{5}{18}\)
\(x-\dfrac{5}{8}=-\dfrac{25}{216}\)
\(x=-\dfrac{25}{216}+\dfrac{5}{8}\)
\(x=\dfrac{55}{108}\)