1/2×x+2/3×x−1=3 1/3
giup mik luon voi a
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
XH
2
27 tháng 2 2021
`1/2x^2(-2x^2y^2z).(-1/3)x^2y^3`
`=1/2 .(-2).(-1/3)x^{2+2+2}.y^{2+3}.z`
`=1/3x^6y^5z`
27 tháng 2 2021
Ta có: \(\dfrac{1}{2}x^2\cdot\left(-2x^2y^2z\right)\cdot\left(-\dfrac{1}{3}\right)x^2y^3\)
\(=\left(\dfrac{1}{2}\cdot2\cdot\dfrac{1}{3}\right)\cdot\left(x^2\cdot x^2\cdot x^2\right)\cdot\left(y^2\cdot y^3\right)\cdot z\)
\(=\dfrac{1}{3}x^6y^5z\)
15 tháng 4 2022
\(∘backwin\)
\(a ) ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750\)
\( ( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750 \)
\( 100 x + ( 1 + 100 ) ×100 : 2 = 5750\)
\(100 x + 5050 = 5750\)
\( 100 x = 5750 − 5050\)
\(100 x = 700\)
\(x = 700 : 100\)
\(x = 7\)
\(b,\) \(B=\)\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{2021^2}< \dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{2020}+2021\)
\( B < 1 -\)\(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2020}-\dfrac{1}{2021}\)
\(B<1-\)\(\dfrac{1}{2021}\)
\(B<\)\(\dfrac{2020}{2021}\)
\(\dfrac{2020}{2021}< 1\)
\(B<1\)
TL
15 tháng 4 2022
a) (x+1) +(x+2 ) + ...+(x+100)=5750
= 100x + (1+2+3+...+100) = 5750
=100x + 5050 = 5750
--> 100x = 5750-5050=700
--> x=7
O
31 tháng 3 2022
\(\dfrac{11}{8}-\dfrac{3}{8}\cdot x=\dfrac{1}{8}\)
\(\dfrac{3}{8}\cdot x=\dfrac{11}{8}-\dfrac{1}{8}\)
\(\dfrac{3}{8}\cdot x=\dfrac{5}{4}\)
\(x=\dfrac{5}{4}:\dfrac{3}{8}\)
\(x=\dfrac{10}{3}\)
31 tháng 3 2022
` 11/8 - 3/8 . x = 1/8 <=> 2/8 . x = 11/8 - 1/8 <=> 2/8x = 10/8 <=> x = 10/8 : 2/8 <=> x = 5 `
H
9 tháng 9 2023
\(\dfrac{5}{7}\times x+\dfrac{2}{5}=\dfrac{2}{3}\\ \dfrac{5}{7}\times x=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{10}{15}-\dfrac{6}{15}=\dfrac{4}{15}\\ x=\dfrac{4}{15}:\dfrac{5}{7}=\dfrac{4\times7}{15\times5}=\dfrac{28}{75}\)
Vậy `x=28/75`
`HaNa☘D`
T
9 tháng 9 2023
\(\dfrac{5}{7}\times x+\dfrac{2}{5}=\dfrac{2}{3}\)
\(\dfrac{5}{7}\times x=\dfrac{2}{3}-\dfrac{2}{5}\)
\(\dfrac{5}{7}\times x=\dfrac{10}{15}-\dfrac{6}{15}\)
\(\dfrac{5}{7}\times x=\dfrac{4}{15}\)
\(x=\dfrac{4}{15}:\dfrac{5}{7}\)
\(x=\dfrac{4}{15}\times\dfrac{7}{5}\)
\(x=\dfrac{28}{75}\)
#Toru
\(=>x\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{10}{3}+1=\dfrac{13}{3}\)
\(=>x=\dfrac{13}{3}:\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{13}{3}:\dfrac{7}{6}=\dfrac{26}{7}\)
5/6x - 1 = 10/3
5/6x = 10/3 + 1 = 13/3
X = 13/3 : 5/6 = 26/5