X : 0,5 + X x 1/5 = 1/3/5 tìm x
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1) \(5-\left(1+\dfrac{1}{3}\right):\left(1-\dfrac{1}{3}\right)\)
\(=5-\dfrac{4}{3}:\dfrac{2}{3}\)
\(=5-\dfrac{4}{3}\cdot\dfrac{3}{2}\)
\(=5-\dfrac{4}{2}\)
\(=5-2\)
\(=3\)
b) \(\left(1+\dfrac{2}{3}-\dfrac{5}{4}\right)-\left(1-\dfrac{5}{4}\right)+2022-\dfrac{2}{3}\)
\(=1+\dfrac{2}{3}-\dfrac{5}{4}-1+\dfrac{5}{4}++2022-\dfrac{2}{3}\)
\(=\left(1-1\right)+\left(\dfrac{2}{3}-\dfrac{2}{3}\right)+\left(-\dfrac{5}{4}+\dfrac{5}{4}\right)+2022\)
\(=0+0+0+2022\)
\(=2022\)
2) \(0,7^2\cdot x=0,49^2\)
\(\Rightarrow x=\dfrac{0,49^2}{0,7^2}\)
\(\Rightarrow x=\left(\dfrac{0,49}{0,7}\right)^2\)
\(\Rightarrow x=\left(0,7\right)^2\)
\(\Rightarrow x=0,49\)
b) \(x:\left(-0,5\right)^3=\left(0,5\right)^2\)
\(\Rightarrow x=\left(0,5\right)^2\cdot\left(-0,5\right)^3\)
\(\Rightarrow x=\left(-0,5\right)^5\)
\(\Rightarrow x=-\dfrac{1}{32}\)
2:
a: =>x*0,49=0,49^2
=>x=0,49
b: =>x=(0,5)^2*(-1)*(0,5)^3=-(0,5)^5
a) \(\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)
0,5 x + 0,6 ( x - 2 ) = 3
0,5 x + 0.6 x - 1,2 = 3
1,1 x = 4,2
x = \(\frac{42}{11}\)
Kết luận:
b) \(\frac{1}{3}x-0,5x=0,75\)
\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)
\(-\frac{1}{6}x=\frac{3}{4}\)
\(x=-\frac{9}{2}\)
Kết luận:
c) \(\frac{3}{-2}x-0,5x=75\%\)
-1,5x - 0,5x = 0,75
-2x = 0,75
x = -0,375
Kết luận:
d) \(-\frac{2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)
-0,4 x + 0,25 = 0,75 - 0,75 x
-0,4 x + 0,75 x = 0,75 - 0,25
0,35 x = 0,5
x = \(\frac{10}{7}\)
Kết luận:
\(a,\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)
\(\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)
\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)
\(\frac{11}{10}x-\frac{6}{5}=3\)
\(\frac{11}{10}x=\frac{21}{5}\)
\(x=\frac{42}{11}\)
\(b,\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)
\(\left(\frac{1}{3}-\frac{1}{2}\right)x=\frac{3}{4}\)
\(\frac{-1}{6}x=\frac{3}{4}\)
\(x=\frac{-9}{2}\)
\(c,\frac{3}{-2}x-\frac{1}{2}x=75\%\)
\(\left(\frac{3}{-2}-\frac{1}{2}\right)x=\frac{3}{4}\)
\(-2x=\frac{3}{4}\)
\(x=\frac{-3}{8}\)
\(\frac{-2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)
\(\frac{-2}{5}x+\frac{3}{4}x=\frac{3}{4}-\frac{1}{4}\)
\(\left(\frac{-2}{5}+\frac{3}{4}\right)x=\frac{1}{2}\)
\(\frac{7}{20}x=\frac{1}{2}\)
\(x=\frac{10}{7}\)
a. |x-1/5|=|-5/2|-|1/4-2/3|
=> |x-1/5|=5/2-5/12
=> |x-1/5|=25/12
+) x-1/5=25/12
=> x=137/60
+) x-1/5=-25/12
=> x=-113/60
Vậy x \(\in\){-113/60 ; 137/60}
b. (x-0,5).(x2-1,96)=0
+) x-0,5=0
=> x=0,5
+) x2-1,96=0
=> x2=1,96
=> x2=(7/5)2=(-7/5)2
=> x \(\in\left\{-\frac{7}{5};\frac{7}{5}\right\}\)
Vậy \(x\in\left\{-\frac{7}{5};0,5;\frac{7}{5}\right\}\).
c. 5/6 : x = 20 : 3
=> 5/6 : x = 20/3
=> x = 5/6 : 20/3
=> x=1/8
Vậy x=1/8.
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a/|x|-2,5=27,5
=>|x|=27,5+2,5=30
=>x=30 hoặc x=-30
b/\(\dfrac{3}{4}+\dfrac{2}{5}.x=\dfrac{29}{60}\)
=>\(\dfrac{2}{5}.x\)=\(\dfrac{29}{60}-\dfrac{3}{4}\)=\(\dfrac{-4}{15}\)
=>x=\(\dfrac{-4}{15}:\dfrac{2}{5}\)=\(\dfrac{-2}{3}\)
c/(x-1)\(^5\)=-32
=>x-1=-2 vì (-2)\(^5\)=-32
=>x=-2+1=-1
d/\(\dfrac{4}{5}.x+0,5=4.5\)
=>\(\dfrac{4}{5}.x+0,5=20\)
=>\(\dfrac{4}{5}.x=20-0,5=19,5\)
=>\(x=19,5:\dfrac{4}{5}\)=\(\dfrac{195}{8}\)
1/3 - 5/6 ( x + 1 ) = 0,5
1/3 - 5/6 ( x + 1 ) = 1/2
5/6 ( x + 1 ) = 1/3 - 1/2
5/6 ( x + 1 ) = -1/6
x + 1 = -1/6 : 5/6
x +1 = -1/5
x = -1/5 - 1
x = -6/5
\(\frac{1}{3}-\frac{5}{6}.\left(x+1\right)=0.5\)
\(\frac{5}{6}.\left(x+1\right)=\frac{1}{3}-0.5\)
\(\frac{5}{6}.\left(x+1\right)=\frac{-1}{6}\)
\(x+1=\frac{-1}{6}:\frac{5}{6}\)
\(x+1=\frac{-1}{5}\)
\(x=\frac{-1}{5}-1\)
\(x=\frac{-6}{5}\)
Vậy \(x=\frac{-6}{5}\)
CHÚC BẠN HỌC TỐT
\(a,\frac{-2}{3}\div\left(\frac{1}{2}-3x\right)=\frac{5}{3}\)
\(\frac{1}{2}-3x=\frac{-2}{3}\div\frac{5}{3}\)
\(\frac{1}{2}-3x=\frac{-2}{5}\)
\(3x=\frac{1}{2}-\frac{-2}{5}\)
\(3x=\frac{9}{10}\)
\(x=\frac{9}{10}\div3=\frac{3}{10}\)
\(b,\frac{1}{7}\left|x\right|-\frac{4}{5}=\frac{1}{5}\)
\(\frac{1}{7}\left|x\right|=\frac{1}{5}+\frac{4}{5}=1\)
\(\left|x\right|=1\div\frac{1}{7}=7\)
\(\Leftrightarrow x=\pm7\)
-2/3:(1/2-3x)=5/3
(1/2-3x)=5/3.-3/2
(1/2-3x)=-5/2
3x=-5/2+1/2
3x=-3/2
x=-3/2:3/1
x=-3/2.1/3
x=-1/2
\(x:0,5+x\) . \(\dfrac{1}{5}=1\dfrac{3}{5}\)
\(x :\)\(\dfrac{1}{2}+x.\dfrac{1}{5}=\dfrac{8}{5}\)
\(x . 2+x.\)\(\dfrac{1}{5}=\dfrac{8}{5}\)
\(x\)\((\)\(2+\)\(\dfrac{1}{5}\)\()\) \(=\)\(\dfrac{8}{5}\)
\(x.\)\(\dfrac{11}{5}=\dfrac{8}{5}\)
\(x=\)\(\dfrac{8}{5}:\dfrac{11}{5}\)
\(x=\)\(\dfrac{8}{11}\)
vậy \(x=\)\(\dfrac{8}{11}\)
\(=>x\times\left(2+\dfrac{1}{5}\right)=\dfrac{5}{3}\)
=>\(x\times\dfrac{11}{5}=\dfrac{5}{3}\)
\(x=\dfrac{5}{3}:\dfrac{11}{5}=\dfrac{25}{33}\)