Tìm x biết :
a) \(x.\frac{13}{20}+x:2=\frac{4}{7}\)
b) \(x:1+x:\frac{1}{2}+x:\frac{125}{1000}=60\)
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a, (9-8x)x2=100
9-8x =100:2
9-8x =50
8x =9-50
8x =-41
x =-41:8
x = \(\frac{-41}{8}\)
b, (20-x)x2=60
20-x =60:2
20-x =30
x =20-30
x =-10
c, \(\frac{1}{2}x+\frac{8}{4}=\frac{100}{25}\)
\(\frac{1}{2}x+2=4\)
\(\frac{1}{2}x=4-2\)
\(\frac{1}{2}x=2\)
x =2:\(\frac{1}{2}\)
x =4
d, (90-x)10=1000
90-x =1000:10
90-x =100
x =90-100
x=-10
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1. Tìm x,y biết
a):\(\frac{x}{9}=\frac{13}{6}\Rightarrow6x=13.9\Rightarrow6x=117\Rightarrow x=\frac{117}{6}=\frac{39}{2}\)
b)\(\frac{17}{x}=\frac{51}{57}\Rightarrow51x=17.57\Rightarrow51x=969\Rightarrow x=\frac{969}{51}=19\)
c)\(\frac{x+2}{3}=\frac{4}{9}\Rightarrow9\left(x+2\right)=3.4\Rightarrow9x+18=12\)
\(\Rightarrow9x=12-18\Rightarrow9x=-6\Rightarrow x=\frac{-6}{9}=\frac{-2}{3}\)
d)\(\frac{x+1}{5}=\frac{125}{\left(x+1\right)^2}\Rightarrow5.125=\left(x+1\right)\left(x+1\right)^2\)
\(\Rightarrow5^4=\left(x+1\right)^3\)
2.Lập tỉ lệ thức:
a) Từ 4 số trên, ta có đẳng thức sau: \(2.14=7.4\)
Vậy, các tỉ lệ thức lập được là: \(\frac{2}{7}=\frac{4}{14};\frac{7}{2}=\frac{14}{4};\frac{2}{4}=\frac{7}{14};\frac{4}{2}=\frac{14}{7}\)
b) Từ 4 số trên, ta có đẳng thức sau: \(4.12=6.8\)
Vậy, các tỉ lệ thức lập được là: \(\frac{4}{6}=\frac{8}{12};\frac{6}{4}=\frac{12}{8};\frac{4}{8}=\frac{6}{12};\frac{8}{4}=\frac{12}{6}\)
a,
\(x+\frac{7}{15}=1\frac{1}{20}\)
\(x+\frac{7}{15}=\frac{21}{20}\)
\(x=\frac{21}{20}-\frac{7}{15}=\frac{63}{60}-\frac{28}{60}\)
\(x=\frac{35}{60}=\frac{7}{12}\)
b,
\(\left[3\frac{1}{2}-x\right]\cdot1\frac{1}{4}=\frac{15}{16}\)
\(\left[\frac{7}{2}-x\right]\cdot\frac{5}{4}=\frac{15}{16}\)
\(\frac{7}{2}-x=\frac{15}{16}:\frac{5}{4}=\frac{3}{4}\)
\(\frac{7}{2}-x=\frac{3}{4}\Rightarrow x=\frac{7}{2}-\frac{3}{4}\)
\(x=\frac{11}{4}\)
c,
\(1\frac{1}{5}x+\frac{2}{3}x=\frac{56}{125}\Leftrightarrow\frac{6}{5}x+\frac{2}{3}x=\frac{56}{125}\)
\(\frac{28}{15}x=\frac{56}{125}\Rightarrow x=\frac{6}{25}\)
d,
\(60\%x+0,4x+x:3=2\)
\(\frac{3}{5}x+\frac{2}{5}x+\frac{1}{3}x=2\)
\(\frac{4}{3}x=2\Rightarrow x=\frac{3}{2}\)
Nguyễn Anh Thiện
a)
x + \(\frac{7}{15}\) = \(1\frac{1}{20}\)
X + \(\frac{7}{15}=\frac{21}{20}\)
X \(=\frac{21}{20}-\frac{7}{15}\)
X \(=\frac{63}{60}-\frac{28}{60}=\frac{35}{60}=\frac{7}{12}\)
^^ Học tốt !
\(a,\)\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=-\frac{37}{45}\)
\(x+\left(\frac{9-5}{5.9}+\frac{13-9}{9.13}+\frac{17-13}{13.17}+...+\frac{45-41}{41.45}\right)=-\frac{37}{45}\)
\(x+\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+....+\frac{1}{41}-\frac{1}{45}\right)-\frac{37}{45}\)
\(x+\left(\frac{1}{5}-\frac{1}{45}\right)=-\frac{37}{45}\)
\(x+\frac{8}{45}=-\frac{37}{45}\)
\(x=-\frac{37}{45}-\frac{8}{45}\)
\(x=-1\)
a) \(2\frac{1}{4}x-9\frac{1}{4}=20\)
\(\frac{9}{4}x=20+\frac{37}{4}\)
\(\frac{9}{4}x=\frac{80}{4}+\frac{37}{4}\)
\(\frac{9}{4}x=\frac{117}{4}\)
\(x=\frac{117}{4}:\frac{9}{4}\)
\(x=\frac{117}{4}.\frac{4}{9}\)
\(x=13\)
Vậy x=13
a) \(2\frac{1}{4}x-9\frac{1}{4}=20\)
\(\Rightarrow\frac{9}{4}x-\frac{37}{4}=20\)
\(\Rightarrow\frac{9}{4}x=20+\frac{37}{4}\)
\(\Rightarrow\frac{9}{4}x=\frac{117}{4}\)
\(\Rightarrow x=\frac{117}{4}:\frac{9}{4}\)
\(\Rightarrow x=13\)
Vậy x = 13
b) \(0,25x-\frac{1}{5}x=\frac{13}{20}\)
\(\Rightarrow\left(0,25-\frac{1}{5}\right)x=\frac{13}{20}\)
\(\Rightarrow\frac{1}{20}x=\frac{13}{20}\)
\(\Rightarrow x=\frac{13}{20}:\frac{1}{20}\)
\(\Rightarrow x=13\)
Vậy x = 13
Ta có : \(\frac{x+1}{5}=\frac{x+2}{6}\)
\(\Rightarrow\left(x+1\right)6=5\left(x+2\right)\)
\(\Leftrightarrow6x+6=5x+10\)
\(\Leftrightarrow6x-5x=10-6\)
\(\Rightarrow x=4\)
\(\frac{x+1}{2}\)= \(\frac{8}{x+1}\)
x + 1 . x + 1 = 2 . 8
x . 2 = 16
x = 16 : 2
x = 8
a) \(x\cdot\frac{13}{20}+x:2=\frac{4}{7}\)
\(x\cdot\frac{13}{20}+x\cdot\frac{1}{2}=\frac{4}{7}\)
\(x\cdot\left(\frac{13}{20}+\frac{1}{2}\right)=\frac{4}{7}\)
\(x\cdot\frac{23}{20}=\frac{4}{7}\)
\(x=\frac{4}{7}:\frac{23}{20}\)
b) \(x:1+x:\frac{1}{2}+x:\frac{125}{1000}=6\)
\(x\cdot\frac{1}{2}+x\cdot2+x\cdot8=6\)
\(x\cdot\left(\frac{1}{2}+2+8\right)=6\)
\(x\cdot\frac{21}{2}=6\)
\(x=6:\frac{21}{2}\)
\(x=\frac{6}{7}\)