a) 24+5.x=75:73
b) 5.x-206=24.4
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\(5.\left(x-1\right)-206=2^4.4\\ \Rightarrow5.\left(x-1\right)-206=16.4\\ \Rightarrow5.\left(x-1\right)-206=64\\ \Rightarrow5.\left(x-1\right)=270\\ \Rightarrow x-1=54\\ \Rightarrow x=55.\)
5.(\(x-1\)) - 206 = 24.4
5.(\(x-1\)) - 206 = 64
5.(\(x-1\)) = 64 + 206
5.(\(x-1\)) = 270
\(x-1\) = 270 : 5
\(x-1\) = 54
\(x=55\)
a: Ta có: \(100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
hay x=11
b: Ta có: \(12\left(x-1\right):3=4^3+2^3\)
\(\Leftrightarrow12\left(x-1\right)=216\)
\(\Leftrightarrow x-1=18\)
hay x=19
a) Ta có: \(\left|x+7\right|-\left(-8\right)=-25+73\)
\(\Leftrightarrow\left|x+7\right|+8=48\)
\(\Leftrightarrow\left|x+7\right|=40\)
\(\Leftrightarrow\left[{}\begin{matrix}x+7=40\\x+7=-40\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=33\\x=-47\end{matrix}\right.\)
Vậy: \(x\in\left\{33;-47\right\}\)
c) Ta có: \(-\left(a-b\right)+\left(b-c\right)-\left(a-c\right)=2b-2a\)
\(\Leftrightarrow-a+b+b-c-a+c=2b-2a\)
\(\Leftrightarrow-2a+2b-2b+2a=0\)
\(\Leftrightarrow0a+0b=0\)(luôn đúng)
Vậy: \(\left\{{}\begin{matrix}a\in Z\\b\in Z\end{matrix}\right.\)
d) Ta có: \(-\left(-a+b+c\right)+\left(b+c-1\right)=-\left(b-a\right)-\left(1-b\right)\)
\(\Leftrightarrow a-b-c+b+c-1=-b+a-1+b\)
\(\Leftrightarrow a-1=a-1\)(luôn đúng)
Vậy: \(\left\{{}\begin{matrix}a\in Z\\b\in Z\\c\in Z\end{matrix}\right.\)
e) Ta có: \(-\left(-a+b+c\right)+\left(b-c+6\right)=a+6\)
\(\Leftrightarrow a-b-c+b-c+6=a+6\)
\(\Leftrightarrow a+6-2c-a-6=0\)
\(\Leftrightarrow-2c=0\)
hay c=0
Vậy: \(\left\{{}\begin{matrix}a\in Z\\b\in Z\\c=0\end{matrix}\right.\)
Giải:
a) \(100-7\left(x-5\right)=31+3^3\)
\(\Leftrightarrow100-7\left(x-5\right)=31+27\)
\(\Leftrightarrow100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
\(\Leftrightarrow x=11\)
Vậy ...
b) \(12\left(x-1\right):3=4^3+2^3\)
\(\Leftrightarrow4\left(x-1\right)=64+8\)
\(\Leftrightarrow4\left(x-1\right)=72\)
\(\Leftrightarrow x-1=18\)
\(\Leftrightarrow x=19\)
Vậy ...
c) \(24+5x=7^5:7^3\)
\(\Leftrightarrow24+5x=7^2\)
\(\Leftrightarrow24+5x=49\)
\(\Leftrightarrow5x=25\)
\(\Leftrightarrow x=5\)
Vậy ...
d) \(5x-206=2^4.4\)
\(\Leftrightarrow5x-206=2^6\)
\(\Leftrightarrow5x-206=64\)
\(\Leftrightarrow5x=270\)
\(\Leftrightarrow x=54\)
Vậy ...
a) 2.(x+4)+5=65
2.(x+4)=65-5
2.(x+4)=60
x+4=60:2
x+4=30
x=30-4=26
a, 100 - 7 ( x - 5 ) = 31 + 33
100 - 7 ( x - 5 ) = 31 + 27
100 - 7 ( x - 5 ) = 58
7 ( x - 5 ) = 100 - 58
7 ( x - 5 ) = 42
x - 5 = 42 : 7
x - 5 = 6
=> x = 6 +5
=> x = 11
Vậy x = 11
b, 12 ( x - 1 ) : 3 = 43 + 23
12 ( x - 1 ) : 3 = 64 + 8
12 ( x - 1 ) : 3 = 72
12 ( x - 1 ) = 72 . 3
12 ( x - 1 ) = 216
x - 1 = 216 : 12
x - 1 = 18
=> x = 18 + 1
=> x = 19
Vậy x = 19
c, 24 + 5x = 75 : 73
24 + 5x = 72
24 + 5x = 49
5x = 49 - 24
5x = 25
=> x = 25 : 5
=> x = 5
Vậy x = 5
d, 5x - 206 = 24 . 4
5x - 206 = 16 . 4
5x - 206 = 64
5x = 64 + 206
5x = 270
=> x = 270 : 5
=> x = 54
Vậy x = 54
e, 125 = x3
53 = x3
=> x = 5
Vậy x = 5
g, 64 = x2
82 = x2
=> x = 8
Vậy x = 8
\(5^x.5^{x+3}=5^4+5^4+5^4+5^4+5^4\\ 5^x\left(1+5^3\right)=5^4\left(1+1+1+1+1\right)\\ 5^x\left(1+125\right)=5^4.5\\ 5^x.126=5^5\\ \dfrac{5^5}{5^x}=126\\ \Rightarrow5-x=126\\ \Rightarrow x=5-126=-121\)
b,
\(24+5x=7^{15}:7^{12}\\ 24+5x=7^3\\ 24+5x=343\\ 5x=343-24\\ 5x=319\\ x=319:5=63,8\)
c,
\(5x-2006=2^4.4\\ 5x-2006=64\\ 5x=64+2006\\ 5x=2017\\ x=2017:5=414\)