Tim x biết
\(\frac{3}{x-2}\)=\(\frac{-2}{\frac{1}{8}}\)
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Khách
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8 tháng 7 2017
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
\(\Leftrightarrow\left(\frac{x+2015}{5}+1\right)+\left(\frac{x+2016}{4}+1\right)=\left(\frac{x+2017}{3}+1\right)+\left(\frac{x+2018}{2}+1\right)\)
\(\Leftrightarrow\frac{x+2020}{5}+\frac{x+2020}{4}-\frac{x+2020}{3}-\frac{x+2020}{2}=0\)
\(\Leftrightarrow\left(x+2020\right)\left(\frac{1}{5}+\frac{1}{4}-\frac{1}{3}-\frac{1}{2}\right)=0\)
\(\Leftrightarrow x+2020=0\)vì \(\frac{1}{5}+\frac{1}{4}+\frac{1}{3}+\frac{1}{2}\ne0\)
\(\Leftrightarrow x=-2020\)
6 tháng 9 2020
a) \(\frac{-8}{x}=\frac{-x}{18}\)
=> x.(-x) = (-8).18
=> -x2 = -144
=> x2 = 144 => x = \(\pm12\)
b) \(\frac{2x+3}{6}=\frac{x-2}{5}\)
=> 5(2x + 3) = 6(x - 2)
=> 10x + 15 - 6x + 12 = 0
=> 4x + 27 = 0
=> 4x = -27
=> x = -27/4
c) \(\frac{x+1}{22}=\frac{6}{x}\)
=> x(x + 1) = 22.6 = 132
=> x(x + 1) = 11.12
=> x = 11
6 tháng 9 2020
\(\frac{-8}{x}=\frac{-x}{18}\)
\(\Leftrightarrow-8\cdot18=x\cdot\left(-x\right)\)
\(\Leftrightarrow-144=-x^2\)
\(\Leftrightarrow144=x^2\)
\(\Leftrightarrow\left(\pm12\right)^2=x^2\)
\(\Leftrightarrow\pm12=x\)
\(\frac{2x+3}{6}=\frac{x-2}{5}\)
\(\Leftrightarrow\left(2x+3\right)\cdot5=6\left(x-2\right)\)
\(\Leftrightarrow10x+15=6x-12\)
\(\Leftrightarrow10x-6x=-12-15\)
\(\Leftrightarrow4x=-27\)
\(\Leftrightarrow x=-\frac{27}{4}\)
\(\frac{x+1}{22}=\frac{6}{x}\)
\(\Leftrightarrow\left(x+1\right)x=22\cdot6\)
\(\Leftrightarrow\left(x+1\right)x=132\)
\(\Leftrightarrow\left(x+1\right)x=12\cdot11\)
\(\Leftrightarrow x=11\)
NT
1
27 tháng 5 2015
\(\frac{1}{2}\left(x+1\right):\frac{3}{7}=\frac{32}{135}\)
\(\frac{1}{2}\left(x+1\right)=\frac{32}{135}.\frac{3}{7}\)
\(\frac{1}{2}\left(x+1\right)=\frac{32}{315}\)
\(x+1=\frac{32}{315}:\frac{1}{2}\)
\(x+1=\frac{64}{315}\)
\(x=\frac{64}{315}-1=-\frac{251}{315}\)
NL
2
NM
17 tháng 11 2017
Ap dung t/c day ti so bang nhau
ta co x+1/9=x+2/8=x+3/7=x+4/6=x+1-x-2-x-3+x+4 tat ca phan 9-8-7+6 =0
N
1 tháng 8 2019
a) \(-\frac{3}{4}x+\frac{1}{6}x=1-2\frac{5}{9}\)
\(\left(-\frac{3}{4}+\frac{1}{6}\right).x=1-\frac{23}{9}\)
\(-\frac{7}{12}.x=-\frac{14}{9}\)
\(x=-\frac{14}{9}:\left(-\frac{7}{12}\right)\)
\(x=\frac{8}{3}\)
Vậy x = ...
b) \(\left|2x-\frac{3}{8}\right|+2\frac{3}{4}=3\frac{1}{16}\)
\(\left|2x-\frac{3}{8}\right|+\frac{11}{4}=\frac{49}{16}\)
\(\left|2x-\frac{3}{8}\right|=\frac{49}{16}-\frac{11}{4}\)
\(\left|2x-\frac{3}{8}\right|=\frac{5}{16}\)
\(\Rightarrow\left|2x-\frac{3}{8}\right|\in\text{{}\frac{5}{16};-\frac{5}{16}\)}
Nếu, \(2x-\frac{3}{8}=\frac{5}{16}\)
\(2x=\frac{11}{16}\)
\(x=\frac{11}{32}\)
Nếu, \(2x-\frac{3}{8}=-\frac{5}{16}\)
\(2x=\frac{1}{16}\)
\(x=\frac{1}{32}\)
Vậy \(x\in\text{{}\frac{1}{32};\frac{11}{32}\)}
29 tháng 10 2018
\(\frac{7}{8}.(\frac{2}{12}+\frac{4}{10})\)
\(\Rightarrow\frac{7}{8}.(\frac{10+24}{60})\)
\(\Rightarrow\frac{7}{8}.\frac{34}{60}=\frac{238}{480}\)
bt2
\(2.x-\frac{5}{4}=\frac{20}{15}\)
\(\Leftrightarrow2x=\frac{20}{15}+\frac{5}{4}\)
\(\Leftrightarrow2x=\frac{80+75}{60}\)
\(\Leftrightarrow2x=2,5\)
\(\Leftrightarrow x=1,25\)
29 tháng 10 2018
.7/8.(1/6+2/5)=7/8.17/30=119/240
3/2-5/6:1/4+\(\sqrt{4}\)=3/2-10/3+2=1/6
2x=20/15+5/4
2x=31/12
x=31/12:2
x=31/24
ko bt nha thông cảm
TT
3
\(\frac{3}{x-2}=\frac{-2}{\frac{1}{8}}\)
\(\Rightarrow\frac{3}{8}=-2\left(x-2\right)\)
\(\frac{3}{8}=-2x-\left(-4\right)\)
\(\frac{3}{8}=-2x+4\)
\(-2x=\frac{3}{8}-4=\frac{-29}{8}\)
\(x=\frac{-29}{8}.\frac{1}{-2}=\frac{29}{16}\)
\(\frac{3}{x-2}=-\frac{2}{\frac{1}{8}}\)
\(\Rightarrow\frac{3}{x-2}=\frac{\left(-2\right).8}{1}\)
\(\Rightarrow\frac{3}{x-2}=-16\)
\(\Rightarrow x-2=3:\left(-16\right)\)
\(\Rightarrow x-2=-\frac{3}{16}\)
\(\Rightarrow x=-\frac{3}{16}+2\)
\(\Rightarrow x=\frac{29}{16}\)