Tìm x :
1 + 5 + 9 + 13 + ............... + x = 501501
giúp mình nha
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1.
7/15:(1/2-9/10xX)-1/6=13/6
=>7/15:(1/2-9/10xX)=13/6+1/6
=>7/16:(1/2-9/10xX)=7/3
=>1/2-9/10xX=7/16:7/3
=>1/2-9/10xX=3/16
=>9/10xX=1/2-3/16
=>9/10xX=5/16
=>X=5/16:9/10
=>X=25/72
X + 5/9 = 4/3
X = 4/3 - 5/9
X = 7/9
X - 4/9 = 1/2
X = 1/2 + 4/9
X = 17/18
6/13 + X = 7/6
X = 7/6 - 6/13
X = 55/78
13/5 - X = 5/6
X = 13/5 - 5/6
X= 53/30
X + 5/9 = 4/3
x = 4/3 - 5/9
x = 7/9
X - 4/9 = 1/2
x = 1/2 + 4/9
x = 17/18
6/13 + X = 7/6
x = 7/6 - 6/13
x - 55/78
13/5 - X = 5/6
x = 13/5 - 5/6
x = 53/30
`a)4/5:3/x xx2/11=24/165`
`(4/5xx2/11)xx 3/x=8/55`
`8/55xx3/x=8/55`
`3/x=8/55:8/55`
`3/x=1`
`3:x=1`
`x=3:1`
`x=3`
____________________________________________
`b)4/3:x/5=5/13xx4/9`
`4/3:x/5=20/117`
`x/5=4/3:20/117`
`x/5=39/5`
`x=39`
A) 4/5:3/x X 2/11=24/165
\(\dfrac{4}{5}:\dfrac{3}{x}X\dfrac{2}{11}=\dfrac{24}{165}\)
\(\dfrac{3}{x}=\dfrac{24}{165}:\dfrac{4}{5}:\dfrac{2}{11}\)
\(\dfrac{3}{x}=1\)
\(\dfrac{3}{x}=\dfrac{3}{3}\)
=> x=3
B) \(\dfrac{4}{3}:\dfrac{x}{5}=\dfrac{5}{13}x\dfrac{4}{9}\)
\(\dfrac{4}{3}:\dfrac{x}{5}=\dfrac{20}{117}\)
\(\dfrac{x}{5}=\dfrac{4}{3}:\dfrac{20}{117}\)
\(\dfrac{x}{5}=\dfrac{39}{5}\)
=> x = 39
13/15-(y.4/15-2/9).3/5=1/5
(y.4/15-2/9).3/5=13/15-1/5
(y.4/15-2/9).3/5=2/3
y.4/15-2/9=2/3:3/5
y.4/15-2/9=10/9
y.4/15=10/9+2/9
y.4/15=4/3
y=4/3:4/15
y=5
Những chỗ có dấu "." thì thay bằng dấu nhân
Ta có : 5= 2+3;9=4+5;13=6+7;...
Do vậy : x=a+(a+1)(a thuộc N)
Nên 1+5+9+13+...+x=1+2+3+4+5+6+7+...+a+(a+1)=501501
Hay (a+1).(a+2) = 1003002 =1001.1002
\(\Rightarrow\)a = 1000.
Vậy x = 1000 + (1000 + 1) = 2001.
17,2001