15 x 3 = ?
12 x 4 = ?
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\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
17 x \(x\) + 15 x \(x\) x 3 + 12 x 15 - \(x\) x 4 = 680
\(x\) x ( 17 + 15 x 3 - 4) + 180 =680
\(x\) x ( 17 + 45 - 4) = 680 - 180
\(x\) x 58 = 500
\(x\) = 500/58
\(x\) = 250/29
17 x \(x\) + 15 x ( \(x\) x 3) + 12 x ( 15 - \(x\) x 4) = 680
17 x \(x\) + 45 x \(x\) + 12 x 15 - 12 x 4 x \(x\) = 680
17 x \(x\) + 45 x \(x\) + 180 - 48 x \(x\) = 680
\(x\) x ( 17 + 45 - 48) + 180 = 680
\(x\) x 14 = 680 - 180
\(x\) x 14 = 500
\(x\) = 500: 14
\(x\) = 250/7
a) 42 - x = 5
x = 42 - 5
x = 37
b) 15.(x + 4) = 75
x + 4 = 75 : 15
x + 4 = 5
x = 5 - 4
x = 1
d) x + 18 = 12
x = 12 - 18
x = -6
e) 2x - 15 = -19
2x = (-19) + 15
2x = -4
x = -4 : 2
x = -2
f) 36 : (x^3 - 12) = -3
x^3 - 12 = 36 : (-3)
x^3 - 12 = -12
x^3 = 0
=> x = 0
g)x + 15 = 35
x = 35 - 15
x = 20
h) 2x - 13 = 3^2
2x - 13 = 9
2x = 9 + 13
2x = 22
x = 22 : 2
x = 11
`= 12 xx 45 + 12 xx 15 + 12 xx 30`
`= 12 xx (45+15+30)`
`= 12 xx 90`
`= 1080`.
Ta có :1.2+2.4+3.6+4.8+5.10/3.4+6.8+9.12+12.16+15.20=[1.2(1+4+9+...+25)]/[3.4(1+4+9+16)]
=(1.2)/(3.4)=2/12=1/6
CHÚC BẠN HỌC TỐT!!
cho tớ nhé!!!!
b: =>x(8-7)=-33
=>x=-33
c: =>-12x+60+21-7x=5
=>-19x=-76
hay x=4
d: =>-2x-2-x+5+2x=0
=>3-x=0
hay x=3
Sửa đề: x^2-16
\(\dfrac{x}{x+4}+\dfrac{x-3}{x-4}-\dfrac{5x-12}{x^2-16}\)
\(=\dfrac{x^2-4x+x^2+x-12-5x+12}{\left(x-4\right)\left(x+4\right)}\)
\(=\dfrac{2x^2-8x}{\left(x-4\right)\left(x+4\right)}=\dfrac{2x}{x+4}\)
15x3=45
12x4=48
...k mik nha!
=45
=48