7x-1/6+2x=16-x/5
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=>5(7x-1)+60x=6(16-x)
=>35x-5+60x-96+6x=0
=>101x=101
hay x=1
\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)
\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)
\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)
\(\Leftrightarrow35x-5+60x=96-6x\)
\(\Leftrightarrow95x-5-96+6x=0\)
\(\Leftrightarrow101x-101=0\\ \Leftrightarrow101x=101\\ \Leftrightarrow x=1\)
20) -5-(x + 3) = 2 - 5x ⇔ -5 - x - 3 = 2 -5x ⇔ 4x = 10 ⇔ x = \(\frac{5}{2}\)
Vậy...
\(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
=> \(\frac{5.\left(7x-1\right)}{30}+\frac{60x}{30}=\frac{6.\left(16-x\right)}{30}\)
=> \(5.\left(7x-1\right)+60x=6.\left(16-x\right)\)
=> \(35x-5+60x=96-6x\)
=> \(35x+6x+60x=5+96\)
=> \(101x=101\)
=> \(x=101:101\)
=>\(x=1\)
c , d giải nốt:
c) 2x + 3/6 = 7x - 13/15
=> (2x + 3) . 15 = (7x - 13) x 6
=> 30x +45 = 42x - 78
=> 30x - 42x = -78 - 45
=> -12x = -123
=> x = 41/4
d) 2-x/4 = 3x - 1/ - 3
=> (2-x) . -3 = 4. (3x - 1)
=> -6 - (-3x) = 12x - 4
(-6) + 4 = 12x - - (-3x)
=> -2 = 9x
=> x = -2/9
\(7x-\dfrac{1}{6}+2x=16-\dfrac{x}{5}\)
\(\dfrac{7x}{1}-\dfrac{1}{6}+\dfrac{2x}{1}=\dfrac{16}{1}-\dfrac{x}{5}\)
\(\dfrac{7x.30}{30}-\dfrac{1.5}{6.5}+\dfrac{2x.30}{1.30}=\dfrac{16.30}{1.30}-\dfrac{x.6}{5.6}\)
\(\dfrac{210x}{30}-\dfrac{5}{30}+\dfrac{60x}{30}=\dfrac{480}{30}-\dfrac{6x}{30}\)
khử mẫu
210x-5+60x=480-6x
=>210x-5+60x-480+6x=0
=>276x-485=0
=>x=485:276
=>x=485/276
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