Viết số thích hợp vào chỗ trống:
\(\dfrac{...}{72}\)=12/36=\(\dfrac{4}{...}\)
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Ta có : \(\dfrac{2}{3}=\dfrac{2.4}{3.4}=\dfrac{8}{12}\)
\(\Rightarrow C\)
\(\dfrac{x}{10}\)=\(\dfrac{12}{-8}\)
->x.(-8)=10.12
->x=\(\dfrac{120}{-8}\)
-> x=-15
Vậy x=-15
\(\dfrac{36}{18}=\dfrac{-10}{-5}=\dfrac{18}{9}=\dfrac{10}{5}\)
a) \(\dfrac{3}{4}=\dfrac{15}{20}\)
b) \(\dfrac{4}{5}=\dfrac{12}{15}\)
c) \(\dfrac{-4}{9}=\dfrac{-16}{36}\)
d) \(\dfrac{7}{-13}=\dfrac{21}{-39}\)
a ) \(\dfrac{3}{4}\)= \(\dfrac{15}{20}\)
b )\(\dfrac{4}{5}\)= \(\dfrac{12}{15}\)
c) \(\dfrac{-4}{9}\)=\(\dfrac{-16}{36}\)
d) \(\dfrac{7}{-13}\)=\(\dfrac{21}{-39}\)
\(\dfrac{5}{6}=\dfrac{10}{12}=\dfrac{30}{36}\)
\(\dfrac{9}{12}=\dfrac{6}{8}=\dfrac{15}{20}\)
gọi
\(\dfrac{12}{39}=\dfrac{x}{12}=\dfrac{36}{y}\)
có `12/39=x/12`
`=> 12xx12=39x`
`=> 39x=144`
`=> x=48/13`
`12/39=36/y`
`=> 36/117=36/y`
`=> y=117`
`
\(\dfrac{24}{72}=\dfrac{12}{36}=\dfrac{4}{12}\)
24/72 = 12/36 = 4/12