2/1/3 : 2/3 +3 x = 14/3
Tìm x
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\(2\frac{1}{3}:\frac{2}{3}+3\cdot x=\frac{14}{3}\)
=>\(\frac{7}{3}:\frac{2}{3}+3.x=\frac{14}{3}\)
=>\(\frac{7}{2}+3.x=\frac{14}{3}\)
=>\(3.x=\frac{14}{3}-\frac{7}{2}\)
=>\(3.x=\frac{7}{6}\)
=>\(x=\frac{7}{6}:3\)
=>\(x=\frac{7}{18}\)
k mk nhìu nha
\(2\frac{1}{3}:\frac{2}{3}+3x=\frac{14}{3}\)
\(\frac{7}{2}+3x=\frac{14}{3}\)
\(3x=\frac{4}{3}\)
\(x=\frac{4}{9}\)
\(\frac{4}{3}-\frac{14}{x}=\frac{2}{5}\)
\(\frac{14}{x}=\frac{4}{3}-\frac{2}{5}\)
\(\frac{14}{x}=\frac{14}{15}\)
\(\Rightarrow\)\(x=15\)
TL:
\(\frac{4}{3}\)- \(\frac{14}{x}\)= \(\frac{2}{5}\)
\(\frac{14}{x}\)= \(\frac{4}{3}\)- \(\frac{2}{5}\)
\(\frac{14}{x}\)= \(\frac{14}{15}\)
x = 15.
~HT~
4.2x-3=125
4.2x=125+3
4.2x=128
2x = 128:4
2x = 32
2x = 25
=> x = 5 ; Vậy x \(\varepsilon\) {5}
(19x+2.52):14=(13-8)2-42
(19x+2.52):14=52-42
(19x+2.52):14=25-16
(19x+2.52):14=9
19x+2.52=9.14
19x+2.52=126
19x+2.25=126
19x+50=126
19x=126-50
19x=76
19x=0 ;Vậy x \(\varepsilon\) {\(\phi\)}
Để \(A\in Z\Leftrightarrow n+2\in U\left(3\right)\)
Ta có bảng sau:
n+2 | -3 | -1 | 1 | 3 |
n | -5 | -3 | -1 | 1 |
Vậy n=... thì A thuộc Z
\(a,x-\frac{5}{6}:1\frac{1}{6}=0,125\)
\(x-\frac{5}{6}:\frac{7}{6}=\frac{1}{8}\)
\(x-\frac{5}{7}=\frac{1}{8}\)
\(x=\frac{1}{8}+\frac{5}{7}\) \(x=\frac{47}{56}\)
\(b,\left(1-\frac{2}{10}+x+\frac{1}{5}\right):\left(1\frac{1}{3}-\frac{2}{3}+3\frac{1}{3}\right)-1=1\frac{1}{2}\)
\(\left(1-\frac{1}{5}+x+\frac{1}{5}\right):\left(\frac{4}{3}-\frac{2}{3}+\frac{10}{3}\right)-1=\frac{3}{2}\)
\(\left(\frac{4}{5}+x+\frac{1}{5}\right):4=\frac{3}{2}+1\)
\(\left(1+x\right):4=\frac{5}{2}\)
\(1+x=\frac{5}{2}.4\)
\(1+x=10\)
\(x=10-1\)
\(x=9\)
1. 6/14+3/x=y/7
3/x= y/7-6/14
3/x=2y-6/14
=> 3/x= y-3/7
=>.21=(y-3)x=7x3=3x7=-7x(-3)=-3x(-7)
=> Lập bảng
.....tự giải nốt
\(2\frac{1}{3}:\frac{2}{3}+3x=\frac{14}{3}\)
\(\frac{7}{3}:\frac{2}{3}+3x=\frac{14}{3}\)
\(\frac{7}{2}+3x=\frac{14}{3}\)
\(3x=\frac{14}{3}-\frac{7}{2}\)
\(3x=\frac{7}{6}\)
\(x=\frac{7}{18}\)