7 : 2/3
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\(x+-\dfrac{1}{9}=-\dfrac{1}{6}\)
\(\Rightarrow x-\dfrac{1}{9}=-\dfrac{1}{6}\)
\(\Rightarrow x=-\dfrac{1}{6}+\dfrac{1}{9}\)
\(\Rightarrow x=-\dfrac{1}{18}\)
_______________
\(5x-3x-\dfrac{5}{6}=\dfrac{2}{3}\)
\(\Rightarrow2x-\dfrac{5}{6}=\dfrac{2}{3}\)
\(\Rightarrow2x=\dfrac{2}{3}+\dfrac{5}{6}\)
\(\Rightarrow2x=\dfrac{3}{2}\)
\(\Rightarrow x=\dfrac{3}{2}:2\)
\(\Rightarrow x=\dfrac{3}{4}\)
<=>\(\left|\dfrac{1}{2}-2x\right|=\dfrac{5}{3}< =>\left[{}\begin{matrix}\dfrac{1}{2}-2x=\dfrac{5}{3}\\\dfrac{1}{2}-2x=\dfrac{-5}{3}\end{matrix}\right.< =>\left[{}\begin{matrix}2x=\dfrac{-7}{6}\\2x=\dfrac{13}{6}\end{matrix}\right.< =>\left[{}\begin{matrix}x=\dfrac{-7}{12}\\x=\dfrac{13}{12}\end{matrix}\right.\)
\(\left|\dfrac{1}{2}+2x\right|+\dfrac{2}{3}=\dfrac{7}{3}\)
\(\left|\dfrac{1}{2}+2x\right|=\dfrac{7}{3}-\dfrac{2}{3}=\dfrac{5}{3}\)
⇔\(\left[{}\begin{matrix}\dfrac{1}{2}+2x=\dfrac{5}{3}\\\dfrac{1}{2}+2x=-\dfrac{5}{3}\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}x=\dfrac{7}{12}\\x=-\dfrac{13}{12}\end{matrix}\right.\)
Vậy ...
a: =5/6(1/8+2/3)=5/6*19/24=95/144
b: =3/4(7/5-1/2)=27/40
c: =35/24*2/3=35/36
12,5+2,6=15,1
37,81-23,5=14,31
4,2x1,4=5,88
17,55:3=5,85
12,5+2,6=15,1
37,81-23,5=14,31
4,2x1,4=5,88
17,55:3=5,85
\(=-7\cdot\left[16+\left(-36\right):\left(-9\right)\right]+125=-77\cdot20+125=-140+125=-15\)
=7 x 3/2=21/2
7x 3/2 = 21/2