10/3 *x+67/4=-13,25
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x+12=3
=> x=3-12
=> x=-9
x+43=67
=> x=67-43
=> x=24
x+23=67
=> x=67-23
=> x=44
a, 2.(4x-3)-3(x+5)+4(x-10)=5(x+2)
2.4x-2.3-3.x+3.5+4x-4.10=5x+5.2
8x-6-3x+15+4x-40=5x-10
8x-3x+4x-5x-6-15-40-10=0
4x-71=0
4x=71
x=71:4
x=71/4
\(S=\dfrac{2}{4\cdot7}+\dfrac{2}{7\cdot10}-\dfrac{3}{5\cdot9}-\dfrac{3}{9\cdot13}\)
\(=\dfrac{2}{3}\left(\dfrac{3}{4\cdot7}+\dfrac{3}{7\cdot10}\right)-\dfrac{3}{4}\left(\dfrac{4}{5\cdot9}+\dfrac{4}{9\cdot13}\right)\)
\(=\dfrac{2}{3}\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}\right)-\dfrac{3}{4}\cdot\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}\right)\)
\(=\dfrac{2}{5}\cdot\dfrac{3}{20}-\dfrac{3}{4}\cdot\dfrac{8}{65}=\dfrac{-21}{650}\)
\(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
\(\Leftrightarrow\) \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{3\left(x+4\right)\left(2-x\right)}{12}+\frac{4\left(x+10\right)\left(2-x\right)}{12}=0\)
\(\Leftrightarrow\) (x + 10)(x + 4) - 3(x + 4)(2 - x) + 4(x + 10)(2 - x) = 0
\(\Leftrightarrow\) x2 + 14x + 40 + 3x2 + 6x - 24 - 4x2 - 32x + 80 = 0
\(\Leftrightarrow\) -12x + 96 = 0
\(\Leftrightarrow\) -12(x - 8) = 0
\(\Leftrightarrow\) x - 8 = 0
\(\Leftrightarrow\) x = 8
Vậy S = {8}
Chúc bn học tốt!!
Bài 1:
b: \(=2\left(4x^2+20x+25\right)+3\left(16x^2-1\right)\)
\(=8x^2+40x+50+48x^2-3\)
\(=56x^2+40x+47\)
Bài 2:
b: \(\Leftrightarrow3x-3+9x-18=2x-6+4x-4\)
=>12x-21=6x-10
=>6x=11
hay x=11/6
x + 5/2 . x - 3/2 = 9/4
<=> x( 1+ 5/2 ) - 3/2 = 9/4
<=> x . 7/2 = 9/4 + 3/2
<=> x .7/2 = 15/4
<=> x = 15/4 : 7/2
<=> x = 15/14
TA CÓ:
X + 5/2 . X - 3/2 = 9/4
X + 5/2 .X = 9/4 +3/2 = 15/4
(X . 1) + (5/2 . X) = 15/4
X . (1 + 5/2) =15/4
X . 7/2 = 15/4
X = (15/4) / (7/2)
X = 15/14
DỄ ÒM MÀ
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Trả lời:
10/3 *x+67/4=-13,25
10/3 x= -30
x= -9