Tìm x thuộc N biết :
a) 2^x . 4 = 128
b) 2^x = 4 . 128
c) 3^x = 3^3 . 3^5
d) 2^x . ( 2^2 ) mũ 3 = ( 2^3 ) mũ 2
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4 tháng 10 2021
b: Ta có: \(2^{x+3}+2^x=144\)
\(\Leftrightarrow2^x\cdot9=144\)
\(\Leftrightarrow2^x=16\)
hay x=4
KV
12 tháng 10 2021
Bài 1
a) \(x=x^5\)
\(x^5-x=0\)
\(x\left(x^4-1\right)=0\)
\(x=0\) hoặc \(x^4-1=0\)
* \(x^4-1=0\)
\(x^4=1\)
\(x=1\)
Vậy x = 0; x = 1
b) \(x^4=x^2\)
\(x^4-x^2=0\)
\(x^2\left(x^2-1\right)=0\)
\(x^2=0\) hoặc \(x^2-1=0\)
*) \(x^2=0\)
\(x=0\)
*) \(x^2-1=0\)
\(x^2=1\)
\(x=1\)
Vậy \(x=0\); \(x=1\)
c) \(\left(x-1\right)^3=x-1\)
\(\left(x-1\right)^3-\left(x-1\right)=0\)
\(\left(x-1\right)\left[\left(x-1\right)^2-1\right]=0\)
\(x-1=0\) hoặc \(\left(x-1\right)^2-1=0\)
*) \(x-1=0\)
\(x=1\)
*) \(\left(x-1\right)^2-1=0\)
\(\left(x-1\right)^2=1\)
\(x-1=1\) hoặc \(x-1=-1\)
**) \(x-1=1\)
\(x=2\)
**) \(x-1=-1\)
\(x=0\)
Vậy \(x=0\); \(x=1\); \(x=2\)
18 tháng 8 2021
Bài 3 :
a) 4.(x-5) - 2 3=24.3
4x-20-8=48
4x=76
x=19
b) 4.x3+15=271
4.x3=256
x3=64
=> x=4
c) ( 2x-3)2= 169
=> 2x-3= 13
2x=16
x=8
Chúc bạn học tốt !
18 tháng 8 2021
4*(x-5) - 2^3 = 2^4*3
4*(x-5) - 8 = 16*3
4*(x-5) - 8 = 48
4*(x-5) = 48 + 8
4*(x-5) = 56
x- 5 = 56 : 4
x - 5 = 14
x = 14 + 5
x = 19
14 tháng 10 2018
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NN
Nguyễn Ngọc Anh Minh
CTVHS
VIP
8 tháng 8 2023
a/
\(x^3-4x^2-\left(x-4\right)=0\)
\(\Leftrightarrow x^2\left(x-4\right)-\left(x-4\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\x-1=0\\x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=1\\x=-1\end{matrix}\right.\)
b/
\(x^5-9x=0\)
\(\Leftrightarrow x\left(x^4-9\right)=x\left(x^2-3\right)\left(x^2+3\right)=0\)
\(\Leftrightarrow x\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\)
c/
\(\left(x^3-x^2\right)^2-4x^2+8x-4=0\)
\(\Leftrightarrow x^4\left(x-1\right)^2-4\left(x-1\right)^2=0\)
\(\Leftrightarrow\left(x-1\right)^2\left(x^4-4\right)=0\)
\(\Leftrightarrow\left(x-1\right)^2\left(x^2-2\right)\left(x^2+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x^2-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\pm\sqrt{2}\end{matrix}\right.\)
ZR
2
HB
14 tháng 10 2018
a) 2x : 4 = 128
=> 2x = 512
=> 2x = 29
=> x = 9
b) x15 = x
=> x15 = x15
=> x = 1 hoặc 0
c) ( 2x + 1 )3 = 125
=> ( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 4
=> x = 2
14 tháng 10 2018
a) 2x : 4 = 128
=> 2x = 128 . 4
=> 2x = 512
=> 2x = 29
=> x = 9
b) x15 = x
=> x15 = x15
=> x = 1 hoặc 0
c) ( 2x + 1 )3 = 125
=> ( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 5 - 1
=> 2x = 4
=> x = 4 : 2
=> x = 2
\(a,2^x.4=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(b,2^x=4.128\)
\(\Leftrightarrow2^x=2^2.2^7\)
\(\Leftrightarrow2^x=2^9\)
\(\Rightarrow x=9\)
\(c,3^x=3^3.3^5\)
\(\Leftrightarrow3^x=3^8\)
\(\Rightarrow x=8\)
\(d,2^x.\left(2^2\right)^3=\left(2^3\right)^2\)
\(\Leftrightarrow2^x.2^6=2^6\)
\(\Leftrightarrow2^x=2^6:2^6\)
\(\Leftrightarrow2^x=1\)
\(\Rightarrow x=0\)
Trả lời:
a, 2x . 4 = 128
=> 2x = 32
=> 2x = 25
=> x = 5
b, 2x = 4.128
=> 2x = 512
=> 2x = 29
=> x = 9
c, 3x = 33 . 35
=> 3x = 38
=> x = 8
d, 2x ( 22 )3 = ( 23 )2
=> 2x . 26 = 26
=> 2x = 1
=> 2x = 20
=> x = 0