\(bai\)\(1\)\(\left(x-\frac{1}{2}\right)^2\)\(=0\)
\(bai\)\(2\)\(\left(x-2\right)^2\)\(=1\)
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\(a,=\dfrac{\left(x-2\right)^2-\left(x+2\right)^2}{\left(x-2\right)^2\left(x+2\right)^2}:\dfrac{x-2+x+2}{\left(x-2\right)\left(x+2\right)}\\ =\dfrac{-8x}{\left(x-2\right)^2\left(x+2\right)^2}\cdot\dfrac{\left(x-2\right)\left(x+2\right)}{2x}=\dfrac{-4}{\left(x-2\right)\left(x+2\right)}\)
\(b,=\dfrac{5x^2+26xy+5y^2+5x^2-26xy+5y^2}{x\left(x-5y\right)\left(x+5y\right)}\cdot\dfrac{\left(x-5y\right)\left(x+5y\right)}{x^2+y^2}\\ =\dfrac{10\left(x^2+y^2\right)}{x\left(x^2+y^2\right)}=\dfrac{10}{x}\)
\(\left(x-\frac{1}{2}\right)^2=0\Rightarrow x-\frac{1}{2}=0\Rightarrow\)\(x=\frac{1}{2}\)
\(\left(x-2\right)^2=1\Rightarrow\hept{\begin{cases}x-2=-1\Rightarrow x=1\\x-2=1\Rightarrow x=3\end{cases}}\Rightarrow x\in\left\{1;3\right\}\)
\(\left(x-\frac{1}{2}\right)^2=0\)
\(\Rightarrow x=\frac{1}{2}\)
\(\left(x-2\right)^2=1\)
\(\Rightarrow x-2=1\)
\(\Rightarrow x=3\)